Question

我有这样的实体：

public class User
{
     public virtual int Id { get; set;}
    public virtual Iesi.Collections.Generic.ISet<Character> Characters { get; set; }
}

public class Character
{
     public virtual int Id { get; set;}
     public virtual User User { get; set;}
    public virtual Iesi.Collections.Generic.ISet<UserCharacterSmartChallengeTracker> SmartChallengeTrackers { get; set; }
}

public class UserCharacterSmartChallengeTracker
{
    public virtual int Id { get; set; }
    public virtual int? CharacterId { get; set; }
}

他们都不是懒惰的。

当我session.Get<User>()时，我看到了这样的疑问：

SELECT smartchall0_.character_id                   as character3_1_,
       smartchall0_.id                             as id1_,
       smartchall0_.id                             as id51_0_,
       smartchall0_.character_id                   as character3_51_0_,
FROM   public.user_character_smart_challenge_trackers smartchall0_
WHERE  smartchall0_.character_id = 48176 /* :p0 */

SELECT smartchall0_.character_id                   as character3_1_,
       smartchall0_.id                             as id1_,
       smartchall0_.id                             as id51_0_,
       smartchall0_.character_id                   as character3_51_0_,
FROM   public.user_character_smart_challenge_trackers smartchall0_
WHERE  smartchall0_.character_id = 48175 /* :p0 */

-- and others

我尝试将所有这些预加载到会话缓存中：

 var ids = session.Query<Character>().Where(x => x.User.Id == id)
            .Select(x => x.Id)
            .ToArray();
 session.Query<UserCharacterSmartChallengeTracker>().Where(x => ids.Contains(x.Id)).ToArray();

查询

select character0_.id as col_0_0_
from   public.characters character0_
where  character0_.user_id = 9602 /* :p0 */
select usercharac0_.id                             as id51_,
       usercharac0_.character_id                   as character3_5
from   public.user_character_smart_challenge_trackers usercharac0_
where  usercharac0_.id in (48176 /* :p0 */, 48175 /* :p1 */, 48174 /* :p2 */, 48173 /* :p3 */,
                           48172 /* :p4 */, 48171 /* :p5 */, 48170 /* :p6 */, 48169 /* :p7 */)

但NHibernate忽略了这样一个事实，即它们都已加载到会话缓存中并生成相同的N + 1个查询！如何解决这个问题？

更新：使用

预加载

session.QueryOver<Character>().Where(x => x.User.Id == id)
                .Fetch(x => x.User).Lazy
                .Fetch(x=>x.SmartChallengeTrackers).Eager
                .List();

删除N + 1但是当我执行session.Get<User>时我会第二次加载NHibernate加载字符！

Answer 1

我使用期货：

        var q = session.Query<User>().Where(x => x.Id == id);

        var lst = new List<IEnumerable>
        {
            q.FetchMany(x => x.Characters).ToFuture(),
            q.Fetch(x=>x.UpdateableData).ToFuture(),
            session.QueryOver<User>().Where(x => x.Id == id)
                .Fetch(x=>x.Characters).Eager
                .Fetch(x => x.Characters.First().SmartChallengeTrackers).Eager
                .Future()
        };

        var r = session.QueryOver<User>().Where(x => x.Id == id)
            .TransformUsing(Transformers.DistinctRootEntity)
            .Future();

        foreach (IEnumerable el in lst)
        {
            foreach (object o in el)
            {

            }
        }

        return r.ToArray();

即使lazy = false，Session.Get也会加载N + 1

1 个答案: