Question

我有三个不同的下拉框，每个下拉框包含一个这三个框共有的列表。我需要过滤列表，

当用户在第一个下拉列表中选择一个选项时，他会去接下来，他不应该在先前选择的列表中获得该选项在第一次下拉列表中。

这是显示两个下拉列表的图像，我需要三个下拉列表 this is the image for two ddwns, but actully i need three of it.

<head>
    <title></title>
    <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
    <script type="text/javascript">
        function cleanMonth(ddl) {
            var val = ddl.options[ddl.selectedIndex].value;

        //Clear all items
        $("#ddlMonth2 > option").remove();

        //Add all options from dropdown 1
        $("#" + ddl.id + "> option").each(function () {
            var opt = document.createElement("option");
            opt.text = this.text;
            opt.value = this.value;
            document.getElementById("ddlMonth2").options.add(opt);
        });

        //Remove selected
        $("#ddlMonth2 option[value='" + val + "']").remove();
    }
</script>

Answer 1

void MainWindow::readSettings()
{
    QSettings settings(QCoreApplication::organizationName(), QCoreApplication::applicationName());
    const QByteArray geometry = settings.value("geometry", QByteArray()).toByteArray();
    const QByteArray windowState = settings.value("windowstate", QByteArray()).toByteArray();
    if (geometry.isEmpty()) {
        const QRect availableGeometry = QApplication::desktop()->availableGeometry(this);
        resize(availableGeometry.width() / 3, availableGeometry.height() / 2);
        move((availableGeometry.width() - width()) / 2,
             (availableGeometry.height() - height()) / 2);
    } else {
        restoreGeometry(geometry);
    }
    if (!windowState.isEmpty()) {
        restoreState(windowState);
    }
}

void MainWindow::writeSettings()
{
    QSettings settings(QCoreApplication::organizationName(), QCoreApplication::applicationName());
    settings.setValue("geometry", saveGeometry());
    settings.setValue("windowState", saveState());
}

此代码将有效......

jQuery代码从列表中选择三个不同的选项，有三个下拉列表？

1 个答案: