如果语句没有执行，为什么最后两个呢？

Question

最后两个elif语句不起作用;它只是将我重定向到前两个中的任何一个。而对于else语句，它不会打印点数。为什么这段代码不起作用？谢谢！

def match_duel():

    print "do you want to swing right or left"
    print "and for how many points?"

    choice = raw_input("> ")
    points = 0
    damage = 0

    if "right" in choice:
        print "you take a swing right. 20 points."
        points = points + 20
        print "You have %d points" % points
        match_duel()
    elif "left" in choice:
        print "you take a swing left. 50 points."
        points = points + 50
        print "You have %d points" % points
        match_duel()
    elif "hard right" in choice:
        print "you take a hard swing right for 100 points."
        print "cthulhu strikes back with 100 points."
        print "you take half the damage."
        points = points + 100
        damage = damage - 50
        print "You have %d points" % points
        print "You have %d damage" % damage
        match_duel()
    elif "hard left" in choice:
        print "you take a hard swing left for 200 points."
        print "cthulhu strikes back with 50 points, taken by surprise."
        print "you take half the damage"
        points = points + 200
        damage = damage - 25
        print "You have %d points" % points
        print "You have %d damage" % damage
        match_duel()
    else:
        print "take an extended hit."
        points = points + 300
        print "You have %d points" % points

Answer 1

此处只能执行一个elif语句。满足条件的第一个将是执行的 - 其余的被忽略。

“left”将始终处于“硬左”状态，无论如何。与“硬权利”相同。因此，底部的2 elif语句将永远不会被执行。