我试图从CSV文件中读取并在Django中创建一个对象（1.9，Py 3.5）但是我收到此错误，无论我将字段更改为
基数为10的int（）的文字无效：＆＃39;＆＃39;
这一行是：
其他=行[＆＃39;其他＆＃39;]
site = Site.objects.create(consolidated_financials = row['Consolidated financials'],
type = Type.objects.get_or_create(name=row['Type'])[0],
tier1_business = Business.objects.get_or_create(tier=1, name=row['Tier-1 business'])[0],
tier2_business = Business.objects.get_or_create(tier=2, name=row['Tier-2 business'])[0],
tier3_business = Business.objects.get_or_create(tier=2, name=row['Tier-3 business'])[0],
site_name = row['Site Name'],
site_id = row['Site ID'],
region = Region.objects.get_or_create(name=row['Region'])[0],
country = Country.objects.get_or_create(name=row['Country'], region=Region.objects.get_or_create(name=row['Region'])[0])[0],
city = City.objects.get_or_create(name=row['City'], country=Country.objects.get_or_create(name=row['Country'], region=Region.objects.get_or_create(name=row['Region'])[0])[0])[0],
site_type = SiteType.objects.get_or_create(name=row['Type of site?'])[0],
remote_site = row['Remote site?'],
finance_manager_name = row['Finance Manager Name'],
finance_manager_sso = row['Finance Manager SSO'],
quarter = row['Quarter'],
revenue = row['Revenue'],
supply_chain_manager_name = row['Supply Chain Manager Name'],
supply_chain_manager_sso = row['Supply Chain Manager SSO'],
product_lines = row['Product Lines'],
manufacturing_processes = row['Manufacturing Processes'],
factory_utilization = row['Factory Utilization'],
fte = row['FTE'],
hourly = row['Hourly'],
salaried = row['Salaried'],
other = row['Other']
)
网站模型：
class Site(models.Model):
"""
Model for a site entry
@author: Leonardo Pessoa
@since: 05/09/2016
"""
from decimal import Decimal
consolidated_financials = models.BooleanField()
type = models.ForeignKey(Type)
tier1_business = models.ForeignKey(Business, limit_choices_to = {'tier': 1}, related_name='%(class)s_tier1')
tier2_business = models.ForeignKey(Business, limit_choices_to = {'tier': 2}, related_name='%(class)s_tier2')
tier3_business = models.ForeignKey(Business, limit_choices_to = {'tier': 3}, related_name='%(class)s_tier3')
site_name = models.CharField(max_length = 150, unique=True)
site_id = models.IntegerField()
region = models.ForeignKey(Region)
country = models.ForeignKey(Country)
city = models.ForeignKey(City)
site_type = models.ForeignKey(SiteType)
remote_site = models.BooleanField()
finance_manager_name = models.CharField(max_length = 50)
finance_manager_sso = models.IntegerField()
quarter = models.DecimalField(max_digits = 12, decimal_places = 2, default=Decimal('0.0'))
revenue = models.DecimalField(max_digits = 12, decimal_places = 2, default=Decimal('0.0'))
supply_chain_manager_name = models.CharField(max_length = 50, default='')
supply_chain_manager_sso = models.IntegerField(default=000000000)
product_lines = models.CharField(max_length = 100, default='')
manufacturing_processes = models.TextField(max_length = 500, default='')
factory_utilization = models.DecimalField(max_digits = 5, decimal_places = 2, default=Decimal('0.0'))
fte = models.IntegerField()
hourly = models.IntegerField()
salaried = models.IntegerField()
other = models.TextField(max_length = 500, default='')
ges_id = models.CharField(max_length = 20)
latitude = models.DecimalField(max_digits = 10, decimal_places=7, default=Decimal('0.0'))
longitude = models.DecimalField(max_digits = 10, decimal_places=7, default=Decimal('0.0'))
行：
row
{'City': 'xxxxxxx',
'Consolidated financials': 'True',
'Country': 'Argentina (AR)',
'FTE': '',
'Factory Utilization': '',
'Finance Manager Name': '',
'Finance Manager SSO': '',
'Hourly': '',
'Manufacturing Processes': '',
'Other': '',
'Product Lines': '',
'Quarter': '',
'Region': 'Latin America',
'Remote site?': 'True',
'Revenue': '',
'Salaried': '',
'Site ID': '12312',
'Site Name': 'xxxxxxxxx',
'Supply Chain Manager Name': '',
'Supply Chain Manager SSO': '',
'Tier-1 business': 'xxxxxxxxxx',
'Tier-2 business': 'xxxxxxxxxxxxx',
'Tier-3 business': 'Latin America',
'Type': 'xxxxxx xxxxx',
'Type of site?': 'Other'}
我知道代码有很大的性能优化空间，但我只是想先证明一下这个功能。
谢谢！
答案 0 :(得分：1)
问题是，您的Site模型希望other成为int（模型是other = IntegerField还是类似？），并且您提供的是空字符串。最简单的解决方法是将row['Other']更改为row['Other'] or 0
如果您知道您将获得非数字值作为一般规则，那么您可以添加基本逻辑来测试非数字，或者将IntegerField更新为可以接受文本的内容。 A list of valid Django fields can be found here
# An example of conditional logic to test for a non-number and use 0 if so
other = row['Other'] if row['Other'] and row['Other'].isdigit() else 0
查看您的模型，问题可能不在于其他字段，但仍存在打字问题。例如Supply Chain Manager SSO应该是一个int，但你肯定传递了''。