Question

我有一个<div class="backgroundOverlay cShow" ng-show="isShownUser"> <div class="dropDown positionPopUp inpuBlock" id="add"> <div class="inputBlock"> <h1 class="popupTitle">{{titlePopup}}</h1> <div> <div class="cClearFloat cInputSpace"> <input placeholder="login" ng-model="currentUser.login"> </div> <div class="cClearFloat cInputSpace"> <input placeholder="Vorname" ng-model="currentUser.Vorname"> </div> <div class="cClearFloat cInputSpace"> <input placeholder="Nachname" ng-model="currentUser.Nachname"> </div> <div class="cClearFloat cInputSpace"> <input placeholder="password" ng-model="currentUser.password"> </div> <div class="cClearFloat cInputSpace cRadioAdmin"> <label><input type="radio" name="Admin">Ja</label> <label><input type="radio" name="Admin">Nein</label> <div class="cClearFloat cButtonsUser"> <button class="cButtonSpeichern" ng-click="showAlert()">Speichern</button> <button class="cButtonAbbrechen" ng-click="isShownUser = false">Abbrechen</button> </div> listField的类。此字段的JSON部分类似于List<BigInteger>。我使用以下代码进行反序列化：

"listField":"[]"

但抛出异常：

com.fasterxml.jackson.databind.JsonMappingException：无法从VALUE_STRING标记中反序列化java.util.ArrayList的实例

fasterxml.jackson 2.2.3版

你能帮帮我，我该如何解决这个问题？

Answer 1

除了自定义反序列化器之外，还可以添加新的setter并忽略old。它帮助了我。

    @JsonProperty("listField")
    public void setListFieldAsString(String listFieldAsString) {
        List<BigInteger> listFieldAsList = new ArrayList<BigInteger>();

        try {
            ObjectMapper objectMapper = new ObjectMapper();
            listFieldAsList = objectMapper.readValue(listFieldAsString, new TypeReference<List<BigInteger>>() {});
        } catch (IOException e) {
            System.out.println("Error was detected!");
        }
        setListField(listFieldAsList);
    }

    @JsonIgnore
    public void setListField(List<BigInteger> listField) {
        this.listField = listField;
    }

反序列化“[]”json为空列表

1 个答案: