在尝试构建彼此依赖的类型时,我碰到了一堵砖墙,这里是代码:
Caused by: graphql.AssertException: type can't be null
at graphql.Assert.assertNotNull(Assert.java:10)
at graphql.schema.GraphQLFieldDefinition.<init>(GraphQLFieldDefinition.java:23)
at graphql.schema.GraphQLFieldDefinition$Builder.build(GraphQLFieldDefinition.java:152)
at graphql_types.GraphQLTypes.createStudentType(GraphQLTypes.java:26)
at graphql_types.GraphQLTypes.<init>(GraphQLTypes.java:19)
它无法实例化这个类,因为我得到了这个异常
Sub FindAndModify()
Dim cel As Range
Dim LookupValue As Double
Dim intRow As Integer
Dim intCol As Integer
Dim celValue As Double
LookupValue = "0.5" 'Define your Lookup Value here or read it from a cell
For Each cel In Sheet1.UsedRange
If cel.Value = LookupValue Then
intRow = cel.Row
intCol = cel.Column
celValue = cel.Value
celValue = celValue + Sheet1.Cells(intRow, 1).Value
celValue = celValue + Sheet1.Cells(1, intCol).Value
MsgBox "Value is " & celValue & " and address is " & cel.Address
'Do stuff with your values
End If
Next cel
End Sub
很明显,classType尚未在createStudentType()引用它时被实例化。如何解决这个问题?
答案 0 :(得分:6)
GraphQLTypeReference确实是答案。这应该这样做:
import graphql.schema.GraphQLList;
import graphql.schema.GraphQLObjectType;
import graphql.schema.GraphQLTypeReference;
import static graphql.Scalars.GraphQLString;
import static graphql.schema.GraphQLFieldDefinition.newFieldDefinition;
import static graphql.schema.GraphQLObjectType.newObject;
public class GraphQLTypes {
private GraphQLObjectType studentType;
private GraphQLObjectType classType;
public GraphQLTypes() {
createStudentType();
createClassType();
}
void createStudentType() {
studentType = newObject().name("Student")
.field(newFieldDefinition().name("name").type(GraphQLString).build())
.field(newFieldDefinition().name("currentClass").type(new GraphQLTypeReference("Class")).build())
.build();
}
void createClassType() {
classType = newObject().name("Class")
.field(newFieldDefinition().name("name").type(GraphQLString).build())
.field(newFieldDefinition().name("students").type(new GraphQLList(studentType)).build())
.build();
}
}
答案 1 :(得分:1)
您是否尝试使用new GraphQLTypeReference("ForwardType")
?我正在谈论这个https://github.com/graphql-java/graphql-java#recursive-type-references