Question

我有以下HTML代码，我试图从中获取URL，但我不太确定如何检索它。我想要得到的href部分是www.boeing.com.au

这是HTML

<a class="ab_button" onmousedown="return rwt(this,'','','','16','AFQjCNFIVYkcHQ-z26ZbnFb9CgYWIbMU7Q','rSHXknRQFBYhkJW2qdZ-Pg','0ahUKEwiv-LLhyODNAhUEORoKHevZDV0Q_BcIhwEwDw','','',event)" 
        role="button" href="/url?sa=t&rct=j&q=&esrc=s&source=web&cd=16&cad=rja&uact=8&ved=0ahUKEwiv-LLhyODNAhUEORoKHevZDV0Q_BcIhwEwDw&url=http%3A%2F%2Fwww.boeing.com.au%2F&usg=AFQjCNFIVYkcHQ-z26ZbnFb9CgYWIbMU7Q&sig2=rSHXknRQFBYhkJW2qdZ-Pg"
        >Website</a>

Answer 1

你应该尝试如下： -

WebElement el = driver.findElement(By.linkText("Website"));
String urlText = el.getAttribute("href"); //this is the url

已修改： -

正如您提到的，您希望www.boeing.com.au来自上面urlText，那么您应该尝试以下方法： -

public static Map<String, String> splitUrl(String urlText)  {
    Map<String, String> query_pairs = new LinkedHashMap<String, String>();
    String query = urlText;
    String[] pairs = query.split("&");
    for (String pair : pairs) {
        int idx = pair.indexOf("=");
        query_pairs.put(URLDecoder.decode(pair.substring(0, idx), "UTF-8"), URLDecoder.decode(pair.substring(idx + 1), "UTF-8"));
    }
    return query_pairs;
}

Map<String, String> splittedUrlMap = splitUrl(urlText);
String actualUrl =  splittedUrlMap.get("url");
System.out.println(actualUrl)'

输出： - http://www.boeing.com.au/

希望它会帮助你...... :)

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