我正在使用这个jsfiddle:http://jsfiddle.net/vaDkF/828/ (没有顶部和底部选项)来创建重新排序表。
$(document).ready(function(){
$(".up,.down").click(function(){
var row = $(this).parents("tr:first");
if ($(this).is(".up")) {
row.insertBefore(row.prev());
} else {
row.insertAfter(row.next());
}
});
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tr>
<td>One</td>
<td>
<a href="#" class="up">Up</a>
<a href="#" class="down">Down</a>
</td>
</tr>
<tr>
<td>Two</td>
<td>
<a href="#" class="up">Up</a>
<a href="#" class="down">Down</a>
</td>
</tr>
<tr>
<td>Three</td>
<td>
<a href="#" class="up">Up</a>
<a href="#" class="down">Down</a>
</td>
</tr>
<tr>
<td>Four</td>
<td>
<a href="#" class="up">Up</a>
<a href="#" class="down">Down</a>
</td>
</tr>
<tr>
<td>Five</td>
<td>
<a href="#" class="up">Up</a>
<a href="#" class="down">Down</a>
</td>
</tr>
</table>
&#13;
我想知道如果它是表格中的第一行,是否可以让向上按钮消失(显示无),如果它是表格中的最后一行,则向下按钮消失。
谢谢!
答案 0 :(得分:6)
您可以使用CSS,first-child
和last-child
选择器:
tr:first-child .up, tr:last-child .down {
display:none;
}
$(document).ready(function() {
$(".up,.down").click(function() {
var row = $(this).parents("tr:first");
if ($(this).is(".up")) {
row.insertBefore(row.prev());
} else {
row.insertAfter(row.next());
}
});
});
&#13;
tr:first-child .up,
tr:last-child .down {
display: none;
}
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tr>
<td>One</td>
<td>
<a href="#" class="up">Up</a>
<a href="#" class="down">Down</a>
</td>
</tr>
<tr>
<td>Two</td>
<td>
<a href="#" class="up">Up</a>
<a href="#" class="down">Down</a>
</td>
</tr>
<tr>
<td>Three</td>
<td>
<a href="#" class="up">Up</a>
<a href="#" class="down">Down</a>
</td>
</tr>
<tr>
<td>Four</td>
<td>
<a href="#" class="up">Up</a>
<a href="#" class="down">Down</a>
</td>
</tr>
<tr>
<td>Five</td>
<td>
<a href="#" class="up">Up</a>
<a href="#" class="down">Down</a>
</td>
</tr>
</table>
&#13;