何我可以与Flink CEP进行懒惰的比赛

时间:2016-07-06 13:30:28

标签: scala apache-flink complex-event-processing flink-cep

我想使用FlinkCEP只做一个懒惰的'匹配模式。我怎样才能做到这一点? 例如我有一个输入流ACABCABCB,我希望在A followBy C上匹配,只获得3场比赛而不是6场比赛。

我创建了以下示例来说明我的问题。

val env = StreamExecutionEnvironment.createLocalEnvironment(1)
env.setStreamTimeCharacteristic(TimeCharacteristic.ProcessingTime)

case class MyEvent(id: Int, kind: String, value: String)
case class MyAggregatedEvent(id: Int, concatenatedValue: String)

val eventStream = env.fromElements(
  MyEvent(1, "A", "1"), MyEvent(1, "C", "1"),
  MyEvent(1, "A", "2"), MyEvent(1, "B", "1"), MyEvent(1, "C", "2"),
  MyEvent(1, "A", "3"), MyEvent(1, "D", "2"), MyEvent(1, "C", "3"),
  MyEvent(1, "B", "3")
)

val pattern: Pattern[MyEvent, _] = Pattern
  .begin[MyEvent]("pA").where(e => e.kind == "A")
  .next("pC").where(e => e.kind == "C")
  .within(Time.seconds(5))

val patternNextStream: PatternStream[MyEvent] = CEP.pattern(eventStream.keyBy(_.id), pattern)

val outNextStream: DataStream[MyAggregatedEvent] = patternNextStream.flatSelect {
  (pattern: scala.collection.mutable.Map[String, MyEvent], collector: Collector[MyAggregatedEvent]) =>
    val partA = pattern.get("pA").get
    val partC = pattern.get("pC").get

    collector.collect(MyAggregatedEvent(partA.id, partA.value + "=>" + partC.value))
}
outNextStream.print()

env.execute("Experiment")

这给了我以下输出:

  

MyAggregatedEvent(1,1 =→1)

当我将模式更改为:

val pattern: Pattern[MyEvent, _] = Pattern
  .begin[MyEvent]("pA").where(e => e.kind == "A")
  .followedBy("pC").where(e => e.kind == "C")
  .within(Time.seconds(5))

然后打印以下内容:

  

MyAggregatedEvent(1,1 =→1)
MyAggregatedEvent(1,1 =→2)
MyAggregatedEvent(1,2 =→2)
MyAggregatedEvent(1,1 =→3)
MyAggregatedEvent(1,2 =→3)
MyAggregatedEvent(1,3 =→3)

如何创建仅匹配每个事件一次的模式,以便我的输出为:

  

MyAggregatedEvent(1,1 =→1)
MyAggregatedEvent(1,2 =→2)
MyAggregatedEvent(1,3 =→3)

1 个答案:

答案 0 :(得分:1)

目前Flink的CEP库不支持此功能。匹配语义尚不能控制。我认为最好先添加MATCH_ALL和匹配MATCH_FIRST模式。一旦看到完全匹配的序列,MATCH_FIRST就会丢弃所有中间状态。这应该涵盖您的用例。