XmlSerializer：参数对象的类型不是原始的

Question

System.InvalidOperationException：参数对象'SI_Foodware.Model.LocalisationCollection'的类型不是原始的。 System.InvalidOperationException：生成XML文档时出错。

LocalisationCollection.cs

using System.Xml.Serialization;

namespace SI_Foodware.Model
{
    [XmlRoot("LocalisationCollection")]
    public class LocalisationCollection
    {
        [XmlArray("LocalisationItems")]
        [XmlArrayItem("LocalisationItem", typeof(LocalisationItem))]
        public LocalisationItem[] LocalisationItem { get; set; }
    }
}

LocalisationItem.cs

using System.Xml.Serialization;
using SQLite.Net.Attributes;

namespace SI_Foodware.Model
{
    public class LocalisationItem
    {
        [PrimaryKey, AutoIncrement]
        [XmlIgnore]
        public int Id { get; set; }

        [XmlElement("Page")]
        public string Page { get; set; }

        [XmlElement("Field")]
        public string Field { get; set; }

        [XmlElement("Language")]
        public string Language { get; set; }

        [XmlElement("Value")]
        public string Value { get; set; }

        [XmlElement("Width")]
        public string Width { get; set; }

        [XmlElement("Columns")]
        public string Columns { get; set; }

        [XmlElement("Table")]
        public string Table { get; set; }

        [XmlElement("Title")]
        public string Title { get; set; }

        [XmlElement("Parent")]
        public string Parent { get; set; }

        [XmlElement("IconSource")]
        public string IconSource { get; set; }

        [XmlElement("TargetType")]
        public string TargetType { get; set; }
   }
}

序列化的功能

    public bool Serialize(string filename)
    {
        var path = GetPath(filename);
        var serializer = new XmlSerializer(typeof(List<LocalisationCollection>));
        var writer = new FileStream(path, FileMode.Create);
        var localisationItems = db.GetAllItems<LocalisationItem>();
        var collection = new LocalisationCollection();

        collection.LocalisationItem = localisationItems.ToArray();

        try
        {
            serializer.Serialize(writer, collection);
            writer.Close();
            return true;
        }
        catch (Exception ex)
        {
            throw new Exception(ex.Message);
        }
    }

我想要这样的想法

<?xml version="1.0" encoding="utf-8"?>
<LocalisationCollection>
    <LocalisationItems>
        <LocalisationItem>
            <Language>Nederlands</Language>
        </LocalisationItem>
        <LocalisationItem>
            <Language>Engels</Language>
        </LocalisationItem>
        <LocalisationItem>
            <Page>LoginPage</Page>
            <Field>grd_grid</Field>
            <Columns>2</Columns>
        </LocalisationItem>
        <LocalisationItem>
            <Page>LoginPage</Page>
            <Field>grd_grid</Field>
            <Width>120</Width>
        </LocalisationItem>
        <LocalisationItem>
            <Page>LoginPage</Page>
            <Field>grd_grid</Field>
            <Width>180</Width>
        </LocalisationItem>
    </LocalisationItems>
</LocalisationCollection>

Answer 1

您正尝试序列化LocalisationCollection XmlSerializer为List<LocalisationCollection>构建：

   var serializer = new XmlSerializer(typeof(List<LocalisationCollection>));
   var collection = new LocalisationCollection();
   serializer.Serialize(writer, collection);

这不起作用。您必须使用为序列化的相同类型构造的序列化程序：

    var serializer = new XmlSerializer(typeof(LocalisationCollection));

为避免此错误，您可以创建以下静态辅助方法：

public static class XmlSerializationHelper
{
    public static void SerializeToFile<T>(this T obj, string path, XmlWriterSettings settings = null, XmlSerializer serializer = null)
    {
        if (obj == null)
            throw new ArgumentNullException("obj");
        using (var stream = new FileStream(path, FileMode.Create))
        using (var writer = XmlWriter.Create(stream, settings))
        {
            serializer = serializer ?? new XmlSerializer(obj.GetType());
            serializer.Serialize(writer, obj);
        }
    }
}

然后您的Serialize方法变为：

    public bool Serialize(string filename)
    {
        var path = GetPath(filename);
        var localisationItems = db.GetAllItems<LocalisationItem>();
        var collection = new LocalisationCollection { LocalisationItem = localisationItems.ToArray() };

        collection.SerializeToFile(path);

        return true;
    }