Question

SELECT type, count(*) as Total 
    FROM table 
WHERE date between ((YEAR(CURDATE())-1900)*1000+DAYOFYEAR(CURDATE())-30) 
   AND (YEAR(CURDATE())-1900)*1000+DAYOFYEAR(CURDATE()) 
   AND rp=100 
   AND pd in ('P7','P9','QU','QL') 
GROUP BY type;

这会产生：

**TYPE**       **TOTAL**
   A               2
   B               4

编辑我的查询是否可行，给我一个像A /（A + B）这样的百分比。我正在努力将单一类型的总值作为分子，并将所有类型的总值作为分母

Answer 1

简单版本，使用子查询返回表格总行数的cte：

with cte as
(
    select type
    from table 
    where date between ((year(CURDATE())-1900)*1000+DAYOFYEAR(CURDATE())-30) 
                    and (year(CURDATE())-1900)*1000+DAYOFYEAR(CURDATE()) 
      and rp = 100 
      and pd in ('P7', 'P9', 'QU', 'QL') 
)
select type, count(*), 100.0 * count(*) / (select count(*) from cte)
from cte
group by type

Answer 2

最简单明了的是：

select type
    , count(*) / (
          select count(*)
          from table 
          where date between ((year(CURDATE())-1900)*1000+DAYOFYEAR(CURDATE())-30) 
           and (year(CURDATE())-1900)*1000+DAYOFYEAR(CURDATE()) 
           and rp=100 
           and pd in ('P7','P9','QU','QL') 
      ) as TotalFraction 
from table 
where date between ((year(CURDATE())-1900)*1000+DAYOFYEAR(CURDATE())-30) 
and (year(CURDATE())-1900)*1000+DAYOFYEAR(CURDATE()) 
and rp=100 
and pd in ('P7','P9','QU','QL') 
group by type;

虽然你可能想利用CTE或临时表来避免重复条件。

Answer 3

我会做类似以下的事情，我想你需要根据你的数据做一些改变

select sum(case when type = 'A' then 1 else 0 end) /
      (sum(case when type = 'A' then 1 else 0 end) + sum(case when type = 'B' then 1 else 0 end)) as Ratio 
from table 
where date between ((year(CURDATE())-1900)*1000+DAYOFYEAR(CURDATE())-30) 
and (year(CURDATE())-1900)*1000+DAYOFYEAR(CURDATE()) 
and rp=100 
and pd in ('P7','P9','QU','QL') ;

Answer 4

SELECT type, Total, CONVERT(decimal, Total)/SUM(Total) OVER() AS Percentage
FROM
(
SELECT type, count(*) as Total 
    FROM table 
WHERE date between ((YEAR(CURDATE())-1900)*1000+DAYOFYEAR(CURDATE())-30) 
   AND (YEAR(CURDATE())-1900)*1000+DAYOFYEAR(CURDATE()) 
   AND rp=100 
   AND pd in ('P7','P9','QU','QL') 
GROUP BY type
) TYPES

编辑查询以包含数学

4 个答案: