Question

在这里，我想找到unique值，所以我正在编写这样的代码，但我无法得到答案，因为我不想要数组格式。我只想要字符串

＆＃13;

<?php
$array = array("kani","yuvi","raja","kani","mahi","yuvi") ;
$unique_array = array(); // unique array
$duplicate_array = array(); // duplicate array
foreach ($array as $key=>$value){
  if(!in_array($value,$unique_array)){
       $unique_array[$key] = $value;
  }else{
     $duplicate_array[$key] = $value;
  }
  }
  echo "unique values are:-<br/>";
  echo "<pre/>";print_r($unique_array);

  echo "duplicate values are:-<br/>";
  echo "<pre/>";print_r($duplicate_array);

?>

＆＃13;

Answer 1

要从数组中获取唯一值，请使用array_unique()：

$array = array(1,2,1,5,10,5,10,7,9,1) ;
array_unique($array);
print_r(array_unique($array));

输出：

Array
(
    [0] => 1
    [1] => 2
    [3] => 5
    [4] => 10
    [7] => 7
    [8] => 9
)

要在数组中使用array_count_values()获取重复值：

$array = array(1,2,1,5,10,5,10,7,9,1) ;
print_r(array_count_values($array));

输出：

Array
(
    [1] => 3 // 1 is duplicated value as it occurrence is 3 times
    [2] => 1
    [5] => 2 // 5 is duplicated value as it occurrence is 3 times
    [10] => 2 // 10 is duplicated value as it occurrence is 3 times
    [7] => 1
    [9] => 1
)

Answer 2

您可以在单行中使用array_unique()，如下所示： -

<?php

$unique_array = array_unique($array); // get unique value from initial array

echo "<pre/>";print_r($unique_array); // print unique values array
?>

输出： - https://eval.in/601260

参考： - http://php.net/manual/en/function.array-unique.php

如果您想要字符串格式： -

echo implode(',',$final_array);

输出： - https://eval.in/601261

你想要的方式是： -

https://eval.in/601263

OR

https://eval.in/601279

Answer 3

<?php
  $arr1 = [1,1,2,3,4,5,6,3,1,3,5,3,20];    
  print_r(arr_unique($arr1)); // will print unique values
  echo "<br>";
  arr_count_val($arr1); // will print array with duplicate values

  function arr_unique($arr) {
    sort($arr);
    $curr = $arr[0];
    $uni_arr[] = $arr[0];
    for($i=0; $i<count($arr);$i++){
       if($curr != $arr[$i]) {
         $uni_arr[] = $arr[$i];
         $curr = $arr[$i];
       }
    }
    return $uni_arr;
  }

  function arr_count_val($arr) {
    $uni_array = arr_unique($arr1);
    $count = 0;

    foreach($uni_array as $n1) {
      foreach($arr as $n1) {
        if($n1 == $n2) {
          $count++;
        }
      }
    echo "$n1"." => "."$count"."<br>";
    $count=0;
    }
  }
?>

Answer 4

我为您选择的接受答案感到困惑-我无法想象它可能如何满足您的要求。

array_count_values()自PHP4开始可用，所以这是值得一提的英雄。

代码：（Demo）

$array = array("kani","yuvi","raja","kani","mahi","yuvi") ;

$counts = array_count_values($array);  // since php4
foreach ($counts as $value => $count) {
    if ($count == 1) {
        $uniques[] = $value;
    } else {
        $duplicates[] = $value;
    }
}

echo "unique values: " , implode(", ", $uniques) , "\n";
echo "duplicate values: " , implode(", ", $duplicates);

输出：

unique values: raja, mahi
duplicate values: kani, yuvi

如何在数组中查找唯一值

4 个答案: