Question

我的模型如下：

case class User(uid: Option[Int], email: String, password: String, created_at: Timestamp, updated_at: Timestamp)

case class UserProfile(firstname: String, lastname: String, gender: Int, user_id: Long)

我将表单绑定定义如下：

    val date = new Date()
  val currentTimestamp= new Timestamp(date.getTime());
  val registerForm = Form(
    tuple(
          "user" -> mapping(
            "uid" -> optional(number),
            "email" -> email,
            "password" -> nonEmptyText,
            "created_at" -> ignored(currentTimestamp),
          "updated_at" -> ignored(currentTimestamp)
        )  (User.apply)(User.unapply),
        "profile" -> mapping(
          "firstname"->nonEmptyText,
          "lastname"->nonEmptyText,
          "gender" -> ignored(0),
          "user_id" -> ignored(0L)
        )(UserProfile.apply)(UserProfile.unapply))
    )

现在，我想使用散列来保存密码，然后使用光滑保存/插入数据库。我可以尝试通过创建一个新的User对象来实现它，但这听起来不像有效的方法。

还有其他方法吗？

提前致谢

------------------------------------------编辑1 --- -------------------------------------------------- ----- 这是我的插入逻辑与光滑：

def insert(user: User): Future[Any] = {
    println("coming inside insert of user dao")
    println(user)
//    insertUP(user)
    db.run((Users returning Users.map(_.uid)) += user)
  }

Answer 1

如下：

def insert(user: User): Future[Any] = {
  val hashedPassword = hashPassword(user.password)
  val updatedUser = user.copy(password = hashedPassword)
  db.run((Users returning Users.map(_.uid)) += updatedUser)
}

为密码字段绑定播放框架scala表单对象？

1 个答案: