Question

我必须计算每个官员的情况，其中Survey =＆＃39; abc＆＃39;和活动=＆＃39; FI＆＃39;和（结果=＆＃39; C＆＃39; OR结果=＆＃39; D＆＃39;）

这是我的完整SQL

SELECT officer, NULL,
    SUM(IIF(ISNUMERIC(mkt) = TRUE AND Survey='dasda' AND Activity='FI' AND Outcome = 'C', Totalmin, 0 ) / 60),
    SUM(Non), SUM(ICC), NULL, NULL, NULL, COUNT(IIF(Survey='abc' AND Activity='FI' AND (Outcome='C'or Outcome='D'), Totalmin, 0))
FROM [DB$]
GROUP BY officer " '

问题部分是

Count(IIF(  Survey='abc' and Activity='FI' and (Outcome='C'or Outcome='D'), Totalmin, 0 ))

然而，我生成的结果并没有起作用。计数结果远不止答案。

Answer 1

COUNT()计算非NULL值的数量。由于0不为空，因此会计算。这有两个选择：

COUNT(IIF(Survey='abc' AND Activity='FI' AND Outcome IN ('C', 'D'), Totalmin, NULL))

或

SUM(IIF(Survey='abc' AND Activity='FI' AND Outcome IN ('C', 'D') AND Totalmin IS NOT NULL, 1, 0))

如果按人员分组怎么写？

1 个答案: