我想在同一页面上显示登录信息和注册表单。但是,似乎我们无法在控制器中的不同两个动作中使用不同的表单变量呈现相同的模板。
这就是我的意思;
public void OpenFromFile();
public void Save(DocumentModel model);
public void Edit(DocumentModel model);
public void SetWebServiceState(bool state);
public void SetCurrentElement(DesignerElementTypeA element);
public void SetCurrentElement(DesignerElementTypeB element);
public void SetCurrentElement(DesignerElementTypeC element);
public void StartDrawing(MouseEventArgs e);
public void AddDrawingPoint(MouseEventArgs e);
public void EndDrawing(MouseEventArgs e);
public class Document
{
// Fetches the document service for handling this document
public DocumentService DocumentService { get; }
}
public class DocumentService
{
public void Save(Document document);
}
}
上面我有登录和注册操作。我想通过这种形式'变量到我使用登录操作呈现的相同树枝模板。当我尝试这样做时,我得到以下异常。
class SecurityController extends Controller {
/**
* @Route("/", name="login")
*/
public function loginAction(Request $request)
{
//Check if the user is already authenticated
if($this->container->get('security.authorization_checker')->isGranted('IS_AUTHENTICATED_FULLY')) {
return $this->redirect($this->generateUrl('dashboard'));
}
$authenticationUtils = $this->get('security.authentication_utils');
// get the error if there is one
$error = $authenticationUtils->getLastAuthenticationError();
// last username entered by the user
$lastUsername = $authenticationUtils->getLastUsername();
$this->addFlash(
'welcome',
'Welcome back!'
);
return $this->render(
'::landing.html.twig',
array(
// last username entered by the user
'last_username' => $lastUsername,
'error' => $error,
)
);
$registrationform = $this->get('form.factory')->createNamedBuilder('registrationform', UserType::class);
}
/**
* @Route("/register", name="register")
*/
public function registerAction(Request $request)
{
//Check authentication
if($this->container->get('security.authorization_checker')->isGranted('IS_AUTHENTICATED_FULLY')) {
return $this->redirect($this->generateUrl('dashboard'));
}
// get the authentication utils
$authenticationUtils = $this->get('security.authentication_utils');
// get the login error if there is one
$error = $authenticationUtils->getLastAuthenticationError();
// last username entered by the user
$lastUsername = $authenticationUtils->getLastUsername();
// build the form
$user = new User();
$form = $this->createForm(UserType::class, $user);
// handle the submit (will only happen on POST)
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
$user->setRoles(array('ROLE_USER'));
// Encode the password (you could also do this via Doctrine listener)
$password = $this->get('security.password_encoder')
->encodePassword($user, $user->getPlainPassword());
$user->setPassword($password);
// save the User!
$em = $this->getDoctrine()->getManager();
$em->persist($user);
$em->flush();
$token = new UsernamePasswordToken($user, null, 'main', $user->getRoles());
$this->get('security.token_storage')->setToken($token);
$this->get('session')->set('_security_main', serialize($token));
// ... do any other work - like sending them an email, etc
// maybe set a "flash" success message for the user
$this->addFlash(
'success',
'Please complete your profile now.'
);
$message = \Swift_Message::newInstance()
->setSubject('You have successfully signed up!')
->setFrom('no-reply@kampweb.com')
->setTo($user->getUsername())
->setBody($this->renderView(
':emails:registration.html.twig'),'text/html');
$this->get('mailer')->send($message);
return $this->redirectToRoute('update');
} else{
$errors = $this->get('validator')->validate( $user );
}
return $this->render(
'::landing.html.twig',
array( 'form' => $form->createView(),
'last_username' => $lastUsername,
'error' => $error,
)
);
}
答案 0 :(得分:2)
我会这样做
2枝文件 -
login.html.twig和register.html.twig - 每个文件都由他自己呈现动作
现在第三个twig文件名为baseLogin.html.twig
在这个文件中,我通过调用控制器
来渲染这两个文件(登录和注册)例如
baseLogin.html.twig
<div>
{{ render(controller('UserBundle:Security:login')) }}
</div>
<div>
{{ render(controller('UserBundle:Registration:register')) }}
</div>