我有一些可以使用JTA的类(ejb,webservices,mdb等)。对于某些课程,我需要RESOURCE_LOCAL
(不能注入)。但是我无法引用RESOURCE_LOCAL
的jndi名称。你如何设置tomee和RESOURCE_LOCAL
?我似乎无法在网上找到一个好的例子,我宁愿不在我的persistence.xml
文件中添加任何用户名和密码。
tomee.xml
有这个:
<Resource id="MYDS" type="DataSource">
JdbcDriver com.mysql.jdbc.Driver
JdbcUrl jdbc:mysql://127.0.0.1:3306/maestro
UserName myusername
Password mypassword
JtaManaged false
</Resource>
persistence.xml
看起来像:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0"
xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name = "MYDS" transaction-type = "RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<non-jta-data-source>MYDS</non-jta-data-source>
</persistence-unit>
</persistence>
我在MYDS
查询中使用了名称EntityManagerFactory
,但收到此错误:
Caused by: org.hibernate.engine.jndi.JndiException: Unable to lookup JNDI name [MYDS]
at org.hibernate.engine.jndi.internal.JndiServiceImpl.locate(JndiServiceImpl.java:117)
at org.hibernate.engine.jdbc.connections.internal.DatasourceConnectionProviderImpl.configure(DatasourceConnectionProviderImpl.java:115)
at org.hibernate.boot.registry.internal.StandardServiceRegistryImpl.configureService(StandardServiceRegistryImpl.java:111)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.initializeService(AbstractServiceRegistryImpl.java:234)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.getService(AbstractServiceRegistryImpl.java:206)
at org.hibernate.engine.jdbc.internal.JdbcServicesImpl.buildJdbcConnectionAccess(JdbcServicesImpl.java:260)
at org.hibernate.engine.jdbc.internal.JdbcServicesImpl.configure(JdbcServicesImpl.java:94)
at org.hibernate.boot.registry.internal.StandardServiceRegistryImpl.configureService(StandardServiceRegistryImpl.java:111)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.initializeService(AbstractServiceRegistryImpl.java:234)
at org.hibernate.service.internal.AbstractServiceRegistryImpl.getService(AbstractServiceRegistryImpl.java:206)
at org.hibernate.cfg.Configuration.buildTypeRegistrations(Configuration.java:1887)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1845)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:852)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:845)
at org.hibernate.boot.registry.classloading.internal.ClassLoaderServiceImpl.withTccl(ClassLoaderServiceImpl.java:398)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:844)
at org.hibernate.jpa.HibernatePersistenceProvider.createEntityManagerFactory(HibernatePersistenceProvider.java:75)
... 36 more
Caused by: javax.naming.NameNotFoundException: Name [MYDS] is not bound in this Context. Unable to find [MYDS].
at org.apache.naming.NamingContext.lookup(NamingContext.java:817)
at org.apache.naming.NamingContext.lookup(NamingContext.java:160)
at org.apache.naming.NamingContext.lookup(NamingContext.java:828)
at org.apache.naming.NamingContext.lookup(NamingContext.java:160)
答案 0 :(得分:2)
解决方案似乎是这样(仍在验证): (不是非常直观或记录,添加openejb:资源到JPA和JPA不起作用,从RESOURCE_LOCAL中删除它并且RESOURCE_LOCAL不起作用)
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0"
xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name = "MYDS" transaction-type = "RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<non-jta-data-source>openejb:Resource/MYDS</non-jta-data-source>
</persistence-unit>
<persistence-unit name="MYDSJPA" transaction-type = "JTA">
<provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
<jta-data-source>MYDS</jta-data-source>
</properties>
</persistence-unit>
</persistence>
答案 1 :(得分:0)
你如何获得你的持久性单位?手动?
如果使用注射:
@PersistenceUnit EntityManagerFactory emf;
@PersistenceContect EntityManager em;
TomEE从其简短名称(id在tomee.xml中)为您解析数据源,否则您需要为其提供完整的JNDI名称,我认为这是java:openejb / Resource / MYDS