Question

question on dialing out with Twilio引起了我的注意，特别是：

capability.allowClientOutgoing("APf5250942ec073c9d08848990cbc0ff5e");

查看sample code：

// Install the Java helper library from twilio.com/docs/java/install
import com.twilio.sdk.TwilioRestClient;
import com.twilio.sdk.TwilioRestException;
import com.twilio.sdk.resource.instance.Application;

public class Example { 

  // Find your Account Sid and Token at twilio.com/user/account
  public static final String ACCOUNT_SID = "ACXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX";
  public static final String AUTH_TOKEN = "your_auth_token";

  public static void main(String[] args) throws TwilioRestException {
    TwilioRestClient client = new TwilioRestClient(ACCOUNT_SID, AUTH_TOKEN);

    // Get an object from its sid. If you do not have a sid,
    // check out the list resource examples on this page
    Application app = client.getAccount().getApplication("AP2a0747eba6abf96b7e3c3ff0b4530f6e");
    System.out.println(app.getSmsUrl());

  }
}

它不是更清楚。 ACCOUNT_SID和AUTH_TOKEN很容易复制/粘贴。我在哪里以及如何获取要发送的字符串？

Javadocs说：

getApplication

public Application getApplication(String sid)

Get a given application instance by sid

Parameters:
    sid - The 34 character sid starting with AP

这让我回到了获取SID以发起呼叫的地点和方式。

Answer 1

要求的应用程序ID是TwiML应用程序ID。这些可以通过浏览器https://www.twilio.com/console/voice/dev-tools/twiml-apps/add手动创建，也可以使用Twilio REST API以编程方式创建，如https://www.twilio.com/docs/api/rest/applications#list-post中所述。

主要是应用程序ID会将2个网址：语音和消息回调网址与您的应用程序相关联。这些是Twilio在获取新事件或需求信息时会尝试发出请求的应用程序URL。这些网址应返回TwiML

Answer 2

临时SID为in the portal for testing。但是，this kluge executes通过生成具有新SID的新应用：

private void createApplication(TwilioRestClient client, String accountSID, String authToken, String fromNumber, String toNumber) {
    log.info("createApplication..");
    List<NameValuePair> params = new ArrayList<NameValuePair>();
    params.add(new BasicNameValuePair("FriendlyName", "Phone Me"));
    params.add(new BasicNameValuePair("VoiceUrl", "http://demo.twilio.com/docs/voice.xml"));
    params.add(new BasicNameValuePair("VoiceMethod", "GET"));
    ApplicationFactory appFactory = client.getAccount().getApplicationFactory();
    Application app = null;
    try {
        app = appFactory.create(params);
    } catch (TwilioRestException ex) {
        Logger.getLogger(Twilio.class.getName()).log(Level.SEVERE, null, ex);
    }
    String sid = app.getSid();
    log.info(sid);
    log.info("name\n" + app.getFriendlyName());
    log.info("sms url\n" + app.getSmsUrl());
    log.info("voice url\n" + app.getVoiceUrl());
    makeCall(client, accountSID, authToken, fromNumber, toNumber, sid);
}

我如何获得Twilio SID？

2 个答案: