PHP foreach循环只输出mysql表中的最后一个值

时间:2016-07-05 09:24:05

标签: php foreach

我已经在这个foreach循环中挣扎了一段时间了。我需要做的是从我的数据库表中获取总和值,进行一些计算,然后使用css将它们显示为条形图。但我的foreach循环只给了我表中的最后一个值。任何帮助将不胜感激,这是我的代码示例:

<?php

    $total_query = "select sum(amount_recieved) from reciepts";
    $total_result = safe_query($total_query);

    $total = mysql_fetch_row($total_result);

    $query = "select category_id from customer_categories";
    $result = safe_query($query);

    while($cat_id = mysql_fetch_assoc($result)){

        foreach ($cat_id as $cat) {

            $sum_query = "select sum(amount_recieved) from reciepts where category =".$cat."";
            $sum_result = safe_query($sum_query);

            $sum = mysql_fetch_array($sum_result);

            $percentage = ($sum[0]/$total[0]) * 100;

            echo "
                <li title='".$cat.", NGN ".$sum[0].", ".$percentage."%' class='bar' style='
                   position:absolute; 
                   bottom:0; 
                   left:1%; 
                   float:left; 
                   width:7%; 
                   height:".$percentage."%; 
                   margin-right:1%; 
                   margin-left:1%; 
                   background:#999;'>
                </li>";

            }
    }

?>

2 个答案:

答案 0 :(得分:0)

您的问题是您将数据可能检索到的每个条形放置在完全相同的位置:

        echo "
            <li title='" . $cat . ", NGN " . $sum[0] . ", " . $percentage . "%' class='bar' style='
               position:absolute; 
               bottom:0; 
               left:1%; 
               float:left; 
               width:7%; 
               height:" . $percentage . "%; 
               margin-right:1%; 
               margin-left:1%; 
               background:#999;'>
            </li>";

向左浮动并绝对定位,它们都会被覆盖。无需对这些li元素进行绝对定位,请尝试删除position:absolute;

答案 1 :(得分:0)

试试这个; $ sum_query =“选择sum(amount_recieved)来自reciepts,其中category =”。$ cat ['category_id'];