Question

我试图在php中将1个表单的值转换为另一个表单。在form1中有r字段，如姓名，电子邮件等。在提交表单后，它将转到另一个表单，其中名称，电子邮件值从form1显示。但在我的表单名称中，电子邮件不会以form2显示。这是代码。

form1.php

  <form method="post" name="XIForm" id="XIForm" action="registration.php">
        <p><label>Name</label><br/><input type="text" name="fname" id="fname" value="" style="margin-left:30px;" placeholder="Name"></p>
        <p><label>Email</label><br/><input type="text" name="email" id="email" value="" style="margin-left:30px;" placeholder="Email"></p>

<?php
    include_once 'db.php';
  if(isset($_POST['XISubmit'])) {

         $fname= mysql_real_escape_string($_POST['fname']);
        $email=$_POST['email'];
        $check_email="select * from reg where email='$email'";
        $run1=mysql_query($check_email);

        if(mysql_num_rows($run1)>0){
        echo "<script>alert('email already exits in our database. Please try with Another!')</script>";
        exit(0);
        }
     else{
              $query = "INSERT INTO reg(fname,username,password,cpassword,email) VALUES ('$fname','$username','$password', '$cpassword','$email')";
              $run11=mysql_query($query);
    $to=$_POST['email'];         
   if($run11){
    $_SESSION['sess_user4']=$username;
    echo "<script>alert('Registration Successful')</script>";
    echo "<script>window.open('attachfile.php', '_self')</script>";
    }
    }   
    }
    ?>

Form2.php

<form method="post" name="XIForm" action="attach.php" enctype="multipart/form-data" onSubmit="return validate();">
  <h4 style="color:#6f4617;margin-left:10px;font-size:15px;font-family:Book Antiqua;color:#168eb6">&nbsp;&nbsp;<b>Welcome <?=$_SESSION['sess_user4']?>  </b>
<br/>

<label>Confirm Name</label><br/>
<input type="text" name="name1" id="name1" style="margin-left:30px;" placeholder="Name" value="<?php if(isset($_GET['fname'])) { echo $_GET['fname']; } ?>"  />
<br/><br/>

Answer 1

试试这个或更多PHP Header Location with parameter

//after submitting form
header("Location: form2.php?fname=".$fname);
//then
 isset($_GET['fname']){
        echo $fname;

  }

Answer 2

您正在使用 echo $ _GET ['fname'];但是你是通过表单发送帖子的？

在php中获取文本框的值从1表单到另一个表单

2 个答案: