如何对最低值的arraylist对象进行排序？

Question

ArrayList <ShyForeignStockHolding> aithird = new ArrayList<ShyForeignStockHolding>();

ShyForeignStockHolding shyfrst = new ShyForeignStockHolding (shyPurchaseSharePrice, shyCurrentSharePrice, shyNumberOfShares, shyCompanyName, shyconversionRate1);

aithird.add(shyfrst);

我想按ArrayList

对Currentshare Price进行排序

Answer 1

您可以使用对象的自定义Comparator，假设您使用的是shyCurrentSharePrice的双倍：

List<ShyForeignStockHolding> sFSH = new ArrayList<ShyForeignStockHolding>();
//add Your objects
Collections.sort(sFSH, new Comparator<ShyForeignStockHolding>() {
    @Override public double compare(ShyForeignStockHolding ssh1, ShyForeignStockHolding ssh2) {
        return ssh1.shyCurrentSharePrice + shh2.shyCurrentSharePrice; //descending use - for Ascending
    }

});

Answer 2

使用Java 8，您现在可以轻松地创建一个Comparator（完全避免使用匿名类）。由于这是按升序排列的，因此您可以在该比较器上调用reversed()使其降序。

Comparator<ShyForeignStockHolding> comparator = Comparator.comparing((sh -> sh.getTheVarYouWantToCompareBy())).reversed();
aithird.sort(comparator);