Question

对于我的用例，我尝试在创建时将所有产品类别列表添加到联系人。

class product_category(models.Model):
            _inherit = "product.category" 
            is_checked = fields.Boolean('Don', help="Check this box if this contact make Donation.")
            resRelId = fields.Many2one('res.partner')

class res_partner(models.Model):
        _inherit = "res.partner"
        categs = fields.One2many('product.category','resRelId',String='Halo')
        @api.model
    def create(self, values):
        categs = self.env['product.category'].search([])
        new_id = super(res_partner, self).create(values)
        for i in categs:
            _logger.error(i)
            new_id.write({'categs': i})
        _logger.error(new_id.categs)
        return new_id

我的代码编译没有错误，但我总是在联系人中找到一个空的产品列表，并且我收到了这些警告。

2016-07-04 17:54:46,777 17751 WARNING v8dev openerp.models: Comparing apples and oranges: product.category(1,) == 1 (/home/odoo/odoo-dev/odoo/openerp/osv/fields.py:800)
2016-07-04 17:54:46,777 17751 WARNING v8dev openerp.models: Comparing apples and oranges: product.category(1,) == 2 (/home/odoo/odoo-dev/odoo/openerp/osv/fields.py:802)
2016-07-04 17:54:46,777 17751 WARNING v8dev openerp.models: Comparing apples and oranges: product.category(1,) == 3 (/home/odoo/odoo-dev/odoo/openerp/osv/fields.py:804)
2016-07-04 17:54:46,777 17751 WARNING v8dev openerp.models: Comparing apples and oranges: product.category(1,) == 4 (/home/odoo/odoo-dev/odoo/openerp/osv/fields.py:812)
2016-07-04 17:54:46,777 17751 WARNING v8dev openerp.models: Comparing apples and oranges: product.category(1,) == 5 (/home/odoo/odoo-dev/odoo/openerp/osv/fields.py:818)
2016-07-04 17:54:46,778 17751 WARNING v8dev openerp.models: Comparing apples and oranges: product.category(1,) == 6 (/home/odoo/odoo-dev/odoo/openerp/osv/fields.py:831)
2016-07-04 17:54:46,778 17751 WARNING v8dev openerp.models: Comparing apples and oranges: product.category(3,) == 1 (/home/odoo/odoo-dev/odoo/openerp/osv/fields.py:800)
2016-07-04 17:54:46,778 17751 WARNING v8dev openerp.models: Comparing apples and oranges: product.category(3,) == 2 (/home/odoo/odoo-dev/odoo/openerp/osv/fields.py:802)
2016-07-04 17:54:46,778 17751 WARNING v8dev openerp.models: Comparing apples and oranges: product.category(3,) == 3 (/home/odoo/odoo-dev/odoo/openerp/osv/fields.py:804)
2016-07-04 17:54:46,778 17751 WARNING v8dev openerp.models: Comparing apples and oranges: product.category(3,) == 4 (/home/odoo/odoo-dev/odoo/openerp/osv/fields.py:812)
2016-07-04 17:54:46,778 17751 WARNING v8dev openerp.models: Comparing apples and oranges: product.category(3,) == 5 (/home/odoo/odoo-dev/odoo/openerp/osv/fields.py:818)
2016-07-04 17:54:46,778 17751 WARNING v8dev openerp.models: Comparing apples and oranges: product.category(3,) == 6 (/home/odoo/odoo-

Answer 1

您正在尝试写入one2many字段。那不是你写给One2many的方式。

这是一个从one2many添加和删除的各种方法的简单提示：

(0, 0,  { values })    link to a new record that needs to be created with the given values dictionary
(1, ID, { values })    update the linked record with id = ID (write *values* on it)
(2, ID)                remove and delete the linked record with id = ID (calls unlink on ID, that will delete the object completely, and the link to it as well)
(3, ID)                cut the link to the linked record with id = ID (delete the relationship between the two objects but does not delete the target object itself)
(4, ID)                link to existing record with id = ID (adds a relationship)
(5)                    unlink all (like using (3,ID) for all linked records)
(6, 0, [IDs])          replace the list of linked IDs (like using (5) then (4,ID) for each ID in the list of IDs)

在您的情况下执行此操作的正确方法是：

def create(self, values):
    categs = self.env['product.category'].search([])
    new_id = super(res_partner, self).create(values)
    for i in categs:
        _logger.error(i)
        new_id.write({'categs': (4,i.id)})
    _logger.error(new_id.categs)
    return new_id

Answer 2

有一种最简单的方法可以做到这一点。

@api.model
def create(self, values):
    ## Here categ is a list containing category ids.
    categs = self.env['product.category'].search([]).ids
    values.update({'categs':[(6, 0, categs or [])]})
    return super(res_partner, self).create(values)

将列表添加到one2many

2 个答案: