创建工厂以构建嵌套资源

Question

这些模型之间的关系是

• airport HAS_MANY flights
• flight HAS_MANY flight_skus

如何使用FactoryGirl轻松创建具有父级和祖父级的flight_sku

  before(:all) do
    @airports = AIRPORTS.collect{|airport| FG.create(:airport, code: airport)}
    @flight = FG.create(:flight, from_airport: @airports[0], to_airport: @airports[3])
    @sku = FG.create(:flight_sku, flight: @flight)
    @flight_2 = FG.create(:flight, from_airport: @airports[1], to_airport: @airports[2])
    @sku_2 = FG.create(:flight_sku, flight_id: @flight_2.id)
  end

更新:(不工作版本_

 NoMethodError:
   undefined method `single_room=' for #<Room:0x007fcbed2e3d60>
   Did you mean?  singleton_method



factory :create_rooms_list do
    single_room
    twin_room
end

factory :single_room do
    name "單人房"
    guests 1
end

factory :twin_room do
    name "雙人房"
    guests 2
end

Answer 1

factory :flight_sku do
  other_fields
  flight
end

factory :flight do
  other_fields
  airport
end

factory :airport do
  other_fields
end

通过致电build(:flight_sku)，您可以创建一个flight，其中包含airport和一个新的flight_sku，并设置了所述关联。

通过致电create(:flight_sku)，您将创建所有这些。

通过调用build_stubbed(:flight_sku)，您将创建flight_sku和两个关联的存根资源。