将XML数据写入ASP.NET页面

时间:2010-09-29 04:15:58

标签: c# .net asp.net xml

我想使用XML格式的C#在ASP.NET页面上显示我的数据

<person>
    <email>a@a.com</email>
    <dob>YYYY-MM-DD- HH:MM:SS</dob>
    <city>XYZ</city>
</person>

您是否有任何带示例的代码。

5 个答案:

答案 0 :(得分:7)

在Html格式化您的字符串

然后在那里添加值

添加

Response.ClearHeaders();
Response.AddHeader("content-type", "text/xml");

然后将字符串写入浏览器

    response.write(yourstring);

示例 -

        string str = "<root>" + "<person>" + personName + "</person>";
        str += "<details>";
        str += "<DOB>" + "yyyy-MM-dd hh:mm:ss" + "</DOB>";
        str += "<City> " + "XYZ" + "</City>";
        str += "</details>";
        str += "</root>";
        Response.ClearHeaders();
        Response.AddHeader("content-type", "text/xml");
        Response.Write(str);
        Response.End();

答案 1 :(得分:2)

我给你一个通用的解决方案

创建一个类 **

public class Person
    {
        public string Email { get; set; }
        public string DOB { get; set; }
        public string City { get; set; }
    }

**

之后在您的任何类库中编写此方法

Public Class Utilities
{
    public static XmlElement Serialize(object transformObject)
            {
                XmlElement serializedElement = null;
                try
                {
                    MemoryStream memStream = new MemoryStream();
                    XmlSerializer serializer = new XmlSerializer(transformObject.GetType());
                    serializer.Serialize(memStream, transformObject);
                    memStream.Position = 0;
                    XmlDocument xmlDoc = new XmlDocument();
                    xmlDoc.Load(memStream);
                    serializedElement = xmlDoc.DocumentElement;
                }
                catch (Exception SerializeException)
                {

                }
                return serializedElement;
            }

}

现在在您要执行此任务的页面上编写此主要功能

private void MainMethod()
{
Collection<Person> mPersons = new Collection<Person>();
            //Fill your collection object mPersons with data 
            // I am giving here example for demo
            Person sPerson = new Person();
            sPerson.City = "City 1";
            sPerson.DOB = DateTime.Now.ToString("YYYY-MM-DD HH:MM:SS"); //just for example 
            sPerson.Email = "email_1@email.com";
            mPersons.Add(sPerson);
            //add another class object
            sPerson = new Person();
            sPerson.City = "City 2";
            sPerson.DOB = DateTime.Now.ToString("YYYY-MM-DD HH:MM:SS"); //just for example 
            sPerson.Email = "email_2@email.com";
            mPersons.Add(sPerson);

            XmlElement xE = (XmlElement)Utilities.Serialize(mPersons);
            XmlDocument xDoc = new XmlDocument();
            xDoc.LoadXml(xE.OuterXml.ToString());
            xDoc.Save(Server.MapPath("myFile.xml"));//give your file path name may be in your web application folder   

}

如果您有类对象或数据集

,请尝试此操作

答案 2 :(得分:1)

我建议你使用转发器控制。在此控件中将表添加到其ItemTemplate中。然后在按钮后单击将xmlDataSource绑定到此转发器

  <table>
     <ItemTamplate>
      <tr>
          <td colspan="3"><person></td>
      </tr>
      <tr>
        <td colspan="2"><email><%#Bind('email')%></email></td>
      </tr>
      <tr>
       <td></td> <td></td> <td><dob><%#Bind('date')%></dob></td>
      </tr>
      <tr>
        <td></td> <td></td> <td><city><%#Bind('city')%></city></td>
      </tr>
      <tr>
         <td colspan="3"></email></td>
      </tr>
    </person>
    </ItemTamplate>
    </table>

答案 3 :(得分:1)

using System; using System.Xml; namespace WriteXmlFile { class Class1 { static void Main(string[] args) { // first you have to create the xml file to any location XmlTextWriter textWriter = new XmlTextWriter("D:\TestxmlFile.xml", null); // to write any things you have to Opens the document textWriter.WriteStartDocument();

// Write first element textWriter.WriteStartElement("Person"); textWriter.WriteStartElement("r", "RECORD", "urn:record"); // Write next element textWriter.WriteStartElement("Email", ""); textWriter.WriteString("DOB"); textWriter.WriteString("City"); textWriter.WriteEndElement(); // WriteChars string[] ch = new string[3]; ch[0] = "a@a.com"; ch[1] = "YYYY-MM-DD"; ch[2] = "xyz"; textWriter.WriteStartElement("Char"); textWriter.WriteChars(ch, 0, ch.Length); textWriter.WriteEndElement(); // Ends the document. textWriter.WriteEndDocument(); // close writer textWriter.Close(); } }

}

然后,您将找到所需的输出

答案 4 :(得分:0)

我发现使用真正的XML文档对象服务器端更好,因此您确定要将有效的XML传递给浏览器。

这样的事情:

XmlDocument xml = new XmlDocument();
xml.LoadXml("<xmlcontent />");

Response.Clear();
Response.AddHeader("content-disposition", "attachment;filename=filename.xml");
xml.Save(Response.OutputStream);