Question

我正在尝试使用api.ai创建自己的聊天机器人。

它第一次变好但第二次出现此错误：

   Traceback (most recent call last):
  File "/root/Documents/Projects/Darlene/core/api.py", line 34, in <module>
    main()
  File "/root/Documents/Projects/Darlene/core/api.py", line 28, in main
    speech, action = b.handle(cmd)
  File "/root/Documents/Projects/Darlene/core/api.py", line 15, in handle
    response = self.request.getresponse().read()
  File "/usr/local/lib/python2.7/dist-packages/apiai/requests/request.py", line 133, in getresponse
    return self._connection.getresponse()
  File "/usr/lib/python2.7/httplib.py", line 1123, in getresponse
    raise ResponseNotReady()
httplib.ResponseNotReady

看起来api有问题。但我不确定。这是我的代码：

import apiai
import json



class Bot(object):
    def __init__(self, client_token='<clientToken>'):

        self.AI = apiai.ApiAI(client_token)
        self.request = self.AI.text_request()
        self.request.lang = 'en'

    def handle(self, text):
        self.request.query = text
        response = self.request.getresponse().read()
        speech = str(json.loads(response)['result']['fulfillment']['speech'])
        action = str(json.loads(response)['result']['action'])
        if action is not '':
            return speech, action
        else:
            return speech, None


def main():
    b = Bot()
    while True:
        cmd = raw_input('me; ')
        speech, action = b.handle(cmd)
        print speech
        if action is not None:
            print 'action'

if __name__ == '__main__':
    main()

有没有人知道解决这个问题的方法？

Answer 1

请不要重复使用请求。只为每个阶段创建新请求。同样如下：

def handle(self, text):
    self.request = self.AI.text_request()
    self.request.lang = 'en'

    self.request.query = text
    response = self.request.getresponse().read()
    speech = str(json.loads(response)['result']['fulfillment']['speech'])
    action = str(json.loads(response)['result']['action'])
    if action is not '':
        return speech, action
    else:
        return speech, None

Answer 2

read（）之后

使用decode（＆＃39; utf-8＆＃39;）。

而且，由于您刚开始将代码移至Python 3.5而不是2.7 ...

。

apiai_request.getresponse（）读取（）进行解码（＆＃39; UTF-8＆＃39;））

请注意，不幸的是，他们在他们的例子中命名了＃34;请求＆＃34;因为它与请求库，烧瓶请求等冲突......但这就是生命。

httplib.ResponseNotReady与api.ai

2 个答案:

使用decode（＆＃39; utf-8＆＃39;）。