我有一个时髦的错误让我疯了。任何人都可以帮我找到它吗?尝试使用两个单词来调用该函数,这两个单词的区别仅在于缺少最后一个字符(“garble”vs“garbl”)。该函数返回0而不是预期的1.它应该返回1,对吗?
我试过摆弄数组边界,但这只会导致IndexOutOfRangeExceptions
。
public static class FuzzyStringMatcher
{
private const int DELETION = 0;
private const int INSERTION = 1;
private const int SUBSTITUTION = 2;
private const int TRANSPOSITION = 3;
private const int COST_OF_DELETION = 1;
private const int COST_OF_INSERTION = 1;
private const int COST_OF_TRANSPOSITION = 1;
private const int COST_OF_SUBSTITUTION = 1;
public static int Compute_DamerauLevenshtein_Distance(string a, string b)
{
int[,] rows = new int[a.Length + 1, b.Length + 1];
int cost_ratio;
int[] calculations = new int[4];
//
// Init the array
//
for (int i = 0; i < rows.GetUpperBound(0); i++)
rows[i, 0] = i;
for (int i = 0; i < rows.GetUpperBound(1); i++)
rows[0, i] = i;
for (int aidx = 1; aidx < rows.GetUpperBound(0); aidx++)
{
for (int bidx = 1; bidx < rows.GetUpperBound(1); bidx++)
{
if (a[aidx - 1] == b[bidx - 1])
cost_ratio = 0;
else
cost_ratio = 1;
calculations[DELETION] = rows[aidx - 1, bidx] + COST_OF_DELETION;
calculations[INSERTION] = rows[aidx, bidx - 1] + COST_OF_INSERTION;
calculations[SUBSTITUTION] = rows[aidx - 1, bidx - 1] + cost_ratio * COST_OF_SUBSTITUTION;
calculations[TRANSPOSITION] = int.MaxValue;
if (aidx > 1 && bidx > 1 && a[aidx] == b[bidx - 1] && a[aidx - 1] == b[bidx])
calculations[TRANSPOSITION] = rows[aidx - 2, bidx - 2] + cost_ratio * COST_OF_TRANSPOSITION;
rows[aidx, bidx] = calculations.Min();
}
}
int score = rows[rows.GetUpperBound(0) - 1, rows.GetUpperBound(1) - 1];
if (a.Contains(b) || b.Contains(a))
score = score / 2;
return score;
}
}
上维基百科页面中给出的算法
答案 0 :(得分:3)
+1 Lou Franco。但除此之外,您似乎有很多索引问题(请注意,wiki示例中的所有4个for
周期都包含在内,当从aidx / bidx中减去1时,您实际上需要减去2,因为在wiki示例索引中字符串从1开始。我的版本:
public static int Compute_DamerauLevenshtein_Distance2(string a, string b)
{
int[,] rows = new int[a.Length + 1, b.Length + 1];
int cost_ratio;
int[] calculations = new int[4];
for(int i = 0; i <= rows.GetUpperBound(0); i++)
rows[i, 0] = i;
for(int i = 1; i <= rows.GetUpperBound(1); i++)
rows[0, i] = i;
for(int aidx = 1; aidx <= rows.GetUpperBound(0); aidx++)
{
for(int bidx = 1; bidx <= rows.GetUpperBound(1); bidx++)
{
if(a[aidx - 1] == b[bidx - 1])
cost_ratio = 0;
else
cost_ratio = 1;
calculations[DELETION] = rows[aidx - 1, bidx] + COST_OF_DELETION;
calculations[INSERTION] = rows[aidx, bidx - 1] + COST_OF_INSERTION;
calculations[SUBSTITUTION] = rows[aidx - 1, bidx - 1] + cost_ratio * COST_OF_SUBSTITUTION;
calculations[TRANSPOSITION] = int.MaxValue;
if(aidx > 1 && bidx > 1 && a[aidx - 1] == b[bidx - 2] && a[aidx - 2] == b[bidx - 1])
calculations[TRANSPOSITION] = rows[aidx - 2, bidx - 2] + cost_ratio * COST_OF_TRANSPOSITION;
rows[aidx, bidx] = calculations.Min();
}
}
int score = rows[rows.GetUpperBound(0), rows.GetUpperBound(1)];
return score;
}
答案 1 :(得分:2)
这不在维基百科的文章中:
if (a.Contains(b) || b.Contains(a))
score = score / 2;
因为你的例子也是如此 - 并且整数除以1/2 == 0,那么就可以了。