我正在尝试仅选择带有过滤数据的ng表中的行。使用以下代码过滤表行,但是甚至选择了未显示的行:
控制器:
<script type="text/ng-template" id="checkbox.html">
<input type="checkbox" ng-model="checkboxes.checked" class="select-all" value="">
</script>
<table class="table" ng-table="tableParams" show-filter="true">
<tr ng-repeat="item in $data track by $index">
<td header="'checkbox.html'">
<input type="checkbox" ng-model="checkboxes.items[item.id]">
</td>
<td data-title="'Name'" filter="{'name': 'text'}">
{{item.name}}
</td>
<td data-title="'Gender'" filter="{'gender': 'text'}">
{{item.gender}}
</td>
</tr>
</table>
HTML:
<?php
error_reporting(E_ALL ^ E_DEPRECATED);
$conn = mysql_connect("localhost", "root", "") or die(mysql_error());
mysql_select_db("slcommunitydb") or die(mysql_error());
?>
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8"/>
<title>Google Maps</title>
<!-------- Customizable Css for Map ----------------------------->
<style type="text/css">
body { font: normal 10pt Helvetica, Arial; }
#map { width: 500px; height: 300px; border: 0px; padding: 0px; }
</style>
<!---------------- Java Scripts for Map ----------------->
<script src="http://maps.google.com/maps/api/js?key=xxxxxxxxxxxxxxxx&sensor=false"
type="text/javascript"></script>
<!------------- Java Scripts for Map ------------------->
<script type="text/javascript">
//--------------------- Sample code written by vIr ------------
var icon = new google.maps.MarkerImage("http://maps.google.com/mapfiles/ms/micons/blue.png",
new google.maps.Size(32, 32), new google.maps.Point(0, 0),
new google.maps.Point(16, 32));
var center = null;
var map = null;
var currentPopup;
var bounds = new google.maps.LatLngBounds();
function addMarker(lat, lng, info) {
var pt = new google.maps.LatLng(lat, lng);
bounds.extend(pt);
var marker = new google.maps.Marker({
position: pt,
icon: icon,
map: map
});
var popup = new google.maps.InfoWindow({
content: info,
maxWidth: 300
});
google.maps.event.addListener(marker, "click", function() {
if (currentPopup != null) {
currentPopup.close();
currentPopup = null;
}
popup.open(map, marker);
currentPopup = popup;
});
google.maps.event.addListener(popup, "closeclick", function() {
map.panTo(center);
currentPopup = null;
});
}
function initMap() {
map = new google.maps.Map(document.getElementById("map"), {
center: new google.maps.LatLng(0, 0),
zoom: 14,
mapTypeId: google.maps.MapTypeId.ROADMAP,
mapTypeControl: true,
mapTypeControlOptions: {
style: google.maps.MapTypeControlStyle.HORIZONTAL_BAR
},
navigationControl: true,
navigationControlOptions: {
style: google.maps.NavigationControlStyle.ZOOM_PAN
}
});
<?php
$query = mysql_query("SELECT * FROM salesmapmarkers")or die(mysql_error());
while($row = mysql_fetch_array($query))
{
$name = $row['name'];
$lat = $row['lat'];
$lon = $row['lon'];
$desc = $row['desc'];
echo("addMarker($lat, $lon, '<b>$name</b><br />$desc');\n");
}
?>
center = bounds.getCenter();
map.fitBounds(bounds);
}
</script>
</head>
<body onLoad="initMap()" style="margin:0px; border:0px; padding:0px;">
<div id="map"></div>
</body>
</html>
当通过名称或性别过滤表格时,表格将使用过滤后的数据进行重新呈现。在筛选表时单击“全选”复选框时,将选择筛选的行。不幸的是,当您清除过滤器时,也会选择先前过滤掉的行。选择所有已过滤的行然后触发应该获取所选项的操作时也是如此。 (为操作选择了所有ID。)
我怎样才能选择过滤的行?谢谢。
答案 0 :(得分:1)
好的,我开始工作了。我刚刚向tableData
添加了一个$scope
对象,因此我可以将过滤后的数据存储在那里。这就是我用来检查所选项目的内容。
let sampleData = [{id: 1, name: 'John Doe', gender: 'Male'},
{id: 2, name: 'Jane Doe', gender: 'Female'},
{id: 3, name: 'Mary Jane', gender: 'Female'},
{id: 4, name: 'Mary Poppins', gender: 'Female'}];
$scope.tableData = {
filteredData: [],
checkboxes: {
checked: false,
items: {}
}
};
$scope.tableParams = new NgTableParams({
page: 1,
count: 10
}, {
total: data.length;
getData: ($defer, params) => {
let filter = params.filter();
let count = params.count();
let page = params.page();
let filteredData = filter ? $filter('filter')(data, filter) : data;
params.total(filteredData.length);
$scope.tableData.filteredData = filteredData;
$defer.resolve(filteredData.slice((page - 1) * count, page * count));
}
});
$scope.$watch(() => {
return $scope.tableData.checkboxes.checked;
}, (value) => {
$scope.tableData.filteredData.map((item) => {
$scope.tableData.checkboxes.items[item].id = value;
});
});
$scope.$watch(() => {
return $scope.tableData.checkboxes.items;
}, () => {
let checked = 0;
let unchecked = 0;
let data = $scope.tableData.filteredData;
let total = data.length;
let checkboxes = $scope.tableData.checkboxes;
data.map((item) => {
if (checkboxes.items[item].id) {
checked++;
} else {
unchecked++;
}
});
if (unchecked === 0 || checked === 0) {
checkboxes.checked = checked === total;
}
angular.element($element[0].getElementsByClassName('select-all')).prop('indeterminate', (checked != 0 && unchecked != 0));
});
不确定这是否是最好的方法。此外,当您过滤&gt;时,这不会将select all复选框的状态更改为indeterminate
。全选&gt;清除过滤器。
答案 1 :(得分:0)
在你的第二只手表中,更改为返回$ scope.tableData.filteredData;可以解决你的问题