Question

我想实现类似于mysql search title, description and multi rows tag的搜索。

以下是我的表格：

图书：

+----+-----------------------+-------------+
| id | name                  | description | 
+----+-----------------------+-------------+
|  1 | Me Before You         | [TEXT]      |
|  2 | How To Win Friends... | [TEXT]      |
|  3 | The Girl on the Train | [TEXT]      |
|  4 | After You             | [TEXT]      |
|  5 | We Were Liars         | [TEXT]      |
+----+-----------------------+-------------+

代码：

+----+-----------------------+
| id | tag                   |
+----+-----------------------+
|  1 | romance               |
|  2 | thriller              |
|  3 | fantasy               |
|  4 | science fiction       |
|  5 | drama                 |
|  6 | friends               |
+----+-----------------------+

Books_tags ：

+---------+--------+
| book_id | tag_id |
+---------+--------+
|       1 |      1 |
|       1 |      3 |
|       2 |      3 |
|       3 |      3 |
|       3 |      5 |
|       4 |      1 |
|       4 |      5 |
|       4 |      6 |
|       5 |      2 |
|       5 |      6 |
+---------+--------+

以下是一些示例搜索和所需结果：

'romance'       -> books 1, 4
'friends'       -> books 2, 4, 5
'friends win'   -> books 2
'fantasy'       -> books 2, 3
'fantasy train' -> books 3

在构建SQL查询之前，函数会检查每个给定的关键字，如果它甚至是一次标记。我的问题是，例如，在这种情况下：

案例：3 /
关键词：朋友赢/
标签：朋友

查询：

SELECT SQL_CALC_FOUND_ROWS 
    b.id, b.name, 
    MATCH(b.name) AGAINST('*friends* *win*' IN BOOLEAN MODE) as name_score,
    MATCH(t.tag) AGAINST('friends' IN BOOLEAN MODE)as tag_score
FROM 
    books b
LEFT JOIN 
    books_tags bt ON bt.book_id = b.id
LEFT JOIN 
    tags t ON t.id = bt.tag_id 
WHERE  
    MATCH(b.name) AGAINST('*friends win*' IN BOOLEAN MODE)
    OR MATCH(t.tag) AGAINST('friends' IN BOOLEAN MODE)
GROUP BY 
    b.id
ORDER BY 
    name_score DESC, (tag_score + name_score) DESC

结果：

array (size=3)
  0 => string '2' (length=1)
  1 => string '4' (length=1)
  2 => string '5' (length=1)

在这种情况下，关键字＆＃39;朋友＆＃39;已经匹配标题，因此必须减少条件，不再搜索标签。我该如何解决？

Answer 1

这就是你之后的事情吗？...

数据集

SELECT DISTINCT b.*
              , MATCH(b.name) AGAINST('*friends* *win*' IN BOOLEAN MODE) name_score
           FROM books b 
           LEFT 
           JOIN books_tags bt 
             ON bt.book_id = b.id 
           LEFT 
           JOIN tags t 
             ON t.id = bt.tag_id 
            AND t.tag IN ('friends','win') 
          WHERE t.id IS NULL;

+----+-----------------------+------------+
| id | name                  | name_score |
+----+-----------------------+------------+
|  1 | Me Before You         |          0 |
|  2 | How To Win Friends... |          1 |
|  3 | The Girl on the Train |          0 |
|  4 | After You             |          0 |
|  5 | We Were Liars         |          0 |
+----+-----------------------+------------+

查询和结果

Get-Content

Answer 2

好的，最后我写了一个函数，为我生成一个有效的查询。该功能非常复杂，取决于多个用户输入。 解决方案是连接t.tag和b.name 。这就是我的WHERE条件看起来如何，它对我来说很好用：

... WHERE ap.active='yes'
AND (LOWER(CONCAT_WS(' ', IF(LENGTH(t.tag), t.tag, NULL), IF(LENGTH(b.name), b.name, NULL) )) REGEXP 'friends'
AND LOWER(CONCAT_WS(' ', IF(LENGTH(t.tag), t.tag, NULL), IF(LENGTH(b.name), b.name, NULL) )) REGEXP 'win')
GROUP BY b.id

mysql搜索标题，描述和多行标记（关于条件）

2 个答案: