Question

Textview的文本中包含日期（;），其格式为DateTime.Now.LocalTime。我尝试通过7/4/2016 3:32:40 PM传递这个但是给了我SqlDateTime溢出错误，所以我尝试将其更改为DateTime time = Convert.ToDateTime(time.Text);但是给了我一个不正确的格式错误。可能是什么问题？

以下是我的代码：

DateTime time = DateTime.ParseExact(txt.Text, "MM/dd/yyyy hh:mm:ss tt", CultureInfo.InvariantCulture);

相关代码：

TextView txt = FindViewById<TextView>(Resource.Id.txt);
DateTime time = DateTime.ParseExact(txt.Text, "MM/dd/yyyy hh:mm:ss tt", CultureInfo.InvariantCulture);

// to pass to webservice

userInfo.TimeStamp = time; // TimeStamp is DateTime type

我在网络服务中的代码：

private void DialogBox(object sender, EventArgs eventArgs) // this is for inserting the DateTime value into database
    {
        EmployeeDetails userInfo = new EmployeeDetails();
        DateTime now = DateTime.Now.ToLocalTime();
        TextView txt = FindViewById<TextView>(Resource.Id.txt);

        if (String.IsNullOrWhiteSpace(request.Text))
        {
            Android.Support.V7.App.AlertDialog.Builder builder = new Android.Support.V7.App.AlertDialog.Builder(this, Resource.Style.AppCompatAlertDialogStyle);
            builder.SetTitle("Warning!");
            builder.SetIcon(Resource.Drawable.warning);
            builder.SetMessage("Please specify your comment or suggestion.");
            builder.SetPositiveButton("OK", (s, ev) => { });
            builder.Show();
        }
        else
        {
            txt.Text = now.ToString(); // this is for getting the value of passed datetime for next use
            userInfo.TimeStamp = now;
            _client.InsertToFeedbackTableAsync(userInfo);
        }
    }

private void ClientOnInsertToFeedbackTableCompleted(object sender, InsertToFeedbackTableCompletedEventArgs ea)
    {
        EmployeeDetails userInfo = new EmployeeDetails();
        TextView txt = FindViewById<TextView>(Resource.Id.txt);
        DateTime time = DateTime.ParseExact(txt.Text, "MM/dd/yyyy hh:mm:ss tt", CultureInfo.InvariantCulture);

        string msg = null;

        if (ea.Error != null)
        {
            //blahblah
        }
        else if (ea.Cancelled)
        {
            //blahblah
        }
        else
        {
            msg = null;

            RunOnUiThread(() =>
            {                     
                userInfo.TimeStamp = time;                       

                _client.InsertToAnswersTableRequestAsync(userInfo);
            });
        }
    }

 private void ClientOnInsertToAnswersTableRequestCompleted(object sender, InsertToAnswersTableRequestCompletedEventArgs ea)
    {
        EmployeeDetails userInfo = new EmployeeDetails();
        TextView txt = FindViewById<TextView>(Resource.Id.txt);
        DateTime time = DateTime.ParseExact(txt.Text, "MM/dd/yyyy hh:mm:ss tt", CultureInfo.InvariantCulture);
        string msg = null;

        if (ea.Error != null)
        {
            //blahblah
        }
        else if (ea.Cancelled)
        {
            //blahblah
        }
        else
        { // blahblah}

Answer 1

由于您的日期时间值（例如7/4/2016 3:32:40 PM）可以包含单个数字，不一定包含2位数字，因此您应该使用格式字符串"M/d/yyyy h:m:s tt"到DateTime.ParseExact。

通过webservice将DateTime值传递给SQL数据库时出现SqlDateTime溢出错误

1 个答案: