是否有人创建或完成了基于JSON结构创建菜单和下拉菜单的编程。
以下是我的JSON菜单结构:
[
{"root" : "Input",
"subs" : [
{"sub_name": "CSV Reader","type": "csv",
"subs_level2": [{"sub_name": "Reader 1","type": "csv"},
{"sub_name": "Reader 2","type": "csv"}
]
},
{"sub_name": "DB Connect","type": "db"},
{"sub_name": "Sample Data","type": "sample data"}
]
},
{"root" : "Output",
"subs" : [
{"sub_name": "Output 1","type": "output1"},
{"sub_name": "Output 2","type": "output2"},
{"sub_name": "Output 3","type": "output3"}
]
}
]
这是我最初的javascript:
// setup the main div
//<div id="canvas_dock"></div>
//$('#canvas_dock').append("<div class='node_dropdown'>
//<span>Input (Root)</span>
//<div class='node_dropdown-content'>
//<div id="">CSV Reader</div>
//<div id="">DB Connect</div>
//<div id="">Sample Data</div>
//</div>
//</div>");
//here is the loop
var key = "root", idx = 0;
for(key in nodeTypes){
if(nodeTypes[idx].root != undefined && nodeTypes[idx].root == root_menu){
for(var sub in nodeTypes[idx].subs){
$('#node_dropdown-content').append(nodeTypes[idx].subs[sub].sub_name);
}
}
idx = idx + 1;
}
答案 0 :(得分:-1)
您可以使用Javascript
查看此内容 var JSON =[
{
"root": "Input",
"subs": [
{
"sub_name": "CSV Reader",
"type": "csv",
"subs_level2": [
{
"sub_name": "Reader 1",
"type": "csv"
},
{
"sub_name": "Reader 2",
"type": "csv"
}
]
},
{
"sub_name": "DB Connect",
"type": "db"
},
{
"sub_name": "Sample Data",
"type": "sample data"
}
]
},
{
"root": "Output",
"subs": [
{
"sub_name": "Output 1",
"type": "output1"
},
{
"sub_name": "Output 2",
"type": "output2"
},
{
"sub_name": "Output 3",
"type": "output3"
}
]
}
]
var select = document.getElementById("selector");
for (var i = 0; i < JSON[0].subs.length; i++) {
var option = document.createElement("option");
option.value = i;
option.textContent = JSON[0].subs[i].sub_name;
select.appendChild(option);
};
for refrence https://plnkr.co/edit/FZNFuu1G3KAvPRvPGtqV?p=preview