Question

#Finding the volume of a box
print("Welcome to box volume calculation! Please answer the following questions.")
x = float(raw_input("How wide is the box? ")),
y = float(raw_input("How high is the box? ")),
z = float(raw_input("How long is the box? ")),

"The volume of the box is " + str(x*y*z) + " units cubed."

我收到的错误消息：

Traceback (most recent call last):
File "C:\Python25\Scripts\Randomness.py", line 22, in <module>
"The volume of the box is " + str(x*y*z) + " units cubed."
TypeError: can't multiply sequence by non-int of type 'tuple'

Answer 1

在您要求输入的行中删除逗号。这些行应为：

x = float(raw_input("How wide is the box? "))
y = float(raw_input("How high is the box? "))
z = float(raw_input("How long is the box? "))

解释......表格声明：

x = a, b, c

创建一个由三个元素组成的元组，同样地：

x = a,

创建一个一个元素的元组。所以在这里，声明如下：

x = float(raw_input(...)),

创建一个元素的元组，该元素是您的输入！

Answer 2

你的变量是元组而不是浮点数：

x = float(raw_input("How wide is the box? ")),
#                                            ^

尾随逗号使您的对象成为包含一个浮点数的元组：

>>> x = 2.2,
>>> type(x)
<class 'tuple'>

怎么办？删除所有尾随逗号：

x = float(raw_input("How wide is the box? "))

额外：错误与您不想要的内容有关，解释器正确地假设您正在尝试使用另一个元组扩展元组。但是，元组只能使用整数扩展：

>>> x = 2.2,
>>> x * 5
(2.2, 2.2, 2.2, 2.2, 2.2)

“TypeError：不能将序列乘以'tuple'类型的非int”是什么意思？

2 个答案: