Question

我正在尝试自定义一些使用Generics的ASP.NET Identity Core类。

我的ApplicationUser类：

    //for the target size you have set the width as your tableView's width when it is already displayed on screen.
    //note that when it is accesed inside viewDidLoad the tableView's bounds
    //may be different to the actual bounds it will be displayed with,
    //here I am just using the screen bounds
    let targetSize = CGSize(width: UIScreen.mainScreen().bounds.width, height: 10000)

    //set the tableHeader's size to its size after its layout constraints are resolved
    tableHeader.bounds.size =  tableHeader.systemLayoutSizeFittingSize(targetSize)

    //reassign it as the tableHeaderView to update the height it will be displayed in
    tableView.tableHeaderView = tableHeader

我的ApplicationUserStore类：

public class ApplicationUser : IdentityUser<Guid>//, ApplicationUserClaim, ApplicationRole, ApplicationUserLogin> 
{
    public ApplicationUser() {  }
}

错误讯息为：

＆＃39; AspDotNetCoreFullFramework.Identity的 ApplicationUser public class ApplicationUserStore : UserStore<ApplicationUser, ApplicationRole, ApplicationDbContext, Guid> { public ApplicationUserStore(ApplicationDbContext ctx, IdentityErrorDescriber describer = null) : base(ctx, describer) { } } Microsoft.AspNetCore.Identity.EntityFrameworkCore.UserStore`8 [TUSER，TRole，TContext，TKEY的，TUserClaim，TUserRole，TUserLogin， TUserToken]＆＃39; 违反了类型参数的限制＆＃39; TUser＆＃39;

现在，当我转到UserStore（基类）的.NET实现时：

public class UserStore＆lt; TUser，TRole，TContext，TKey＆gt; ：   UserStore＆lt; TUser，TRole，TContext，TKey，   IdentityUserClaim＆lt; TKey＆gt;，IdentityUserRole＆lt; TKey＆gt;，   IdentityUserLogin＆lt; TKey＆gt;，IdentityUserToken＆lt; TKey＆gt;＆gt;

           TUser：IdentityUser＆lt; TKey＆gt;
            ...           其中TKey：IEquatable＆lt; TKey＆gt;       {

我可以看到ApplicationUser继承自IdentityUser＆lt; GUID＆gt;。满足此约束。 TKey是实现IEquatable＆lt; GUID＆gt;的GUID。这个约束也得到了满足。

那么问题是什么？

Answer 1

将GUID添加到

IdentityBuilder.AddEntityFrameworkStores<ApplicationDbContext,Guid>();

如此post中提到的那样解决了这个问题。

从ApplicationUser到IdentityUser没有隐式引用转换

1 个答案: