Question

我正在使用MySQL，但我认为这是一个基本的SQL问题我不知道还有什么要问，只是举个例子。

说我的表中有这些数据：

id    date_time             foreign_key   key             value
1     2010-01-01 00:00:00   1             'temperature'   84
2     2010-01-01 00:00:01   1             'humidity'      34
3     2010-01-01 00:00:02   2             'temperature'   45
4     2010-01-01 00:00:03   2             'humidity'      23
5     2010-01-01 00:00:04   2             'dew_point'     78
6     2010-01-01 00:00:05   3             'temperature'   57
7     2010-01-01 00:00:06   3             'humidity'      41
8     2010-01-01 00:00:07   4             'temperature'   19
9     2010-01-01 00:00:08   4             'humidity'      35
10    2010-01-01 00:00:09   4             'dew_point'     24
11    2010-01-01 00:00:10   1             'temperature'   84
12    2010-01-01 00:00:11   1             'dew_point'     34
13    2010-01-01 00:00:12   2             'temperature'   45
14    2010-01-01 00:00:13   2             'humidity'      23
15    2010-01-01 00:00:14   3             'dew_point'     57
16    2010-01-01 00:00:15   3             'humidity'      41
17    2010-01-01 00:00:16   4             'temperature'   19
18    2010-01-01 00:00:17   4             'dew_point'     24

如何获取单个foreign_key的最新密钥？

例如，假设我想要最近的外键4，我想要的结果是：

id    date_time             foreign_key   key             value
9     2010-01-01 00:00:08   4             'humidity'      35
17    2010-01-01 00:00:16   4             'temperature'   19
18    2010-01-01 00:00:17   4             'dew_point'     24

我将用什么SQL来实现这个结果？

顺便说一句，我意识到这不是大多数人选择存储这类数据的第一种方式，但我有我的理由。即，这些值是彼此分开报告的。

Answer 1

select m.id, m.date_time, m.foreign_key, m.key, m.value 
from (
    select foreign_key, key, max(date_time) as MaxDate
    from MyTable
    group by foreign_key, key
) mm
inner join MyTable m on mm.foreign_key = m.foreign_key
    and mm.MaxDate = m.date_time
    and mm.key = m.key

Answer 2

~~SELECT * FROM table WHERE foreign_key ='4'ORDER BY date_time ASC LIMIT 3;~~

更新，然后正确的是：

SELECT * FROM `table` WHERE `foreign_key`='4' GROUP BY `key` HAVING `date_time`=MAX(`date_time`) ORDER BY `id`;

Answer 3

select m.id, m.date_time, m.foreign_key, m.key, m.value 
from (
    select foreign_key, key, max(date_time) as MaxDate
    from MyTable
    group by foreign_key, key
) mm
inner join MyTable m on mm.foreign_key=m.foreign_key
    and mm.MaxDate = m.date_time and mm.key = m.key

正如我在上面评论过的那样，应该首先获得RedFilter的信用。

Answer 4

我根据this page的答案找出了答案。查询

SELECT m.id, m.date_time, m.foreign_key, m.key, m.value
FROM MyTable m
LEFT OUTER JOIN MyTable mm
  ON (m.foreign_key = mm.foreign_key
      AND m.key = mm.key
      AND m.date_time < mm.date_time)
WHERE mm.key IS NULL
  AND m.foreign_key=4;

完全符合我的需要。即：

+----+---------------------+-------------+-------------+-------+
| id | date_time           | foreign_key | key         | value |
+----+---------------------+-------------+-------------+-------+
|  9 | 2010-01-01 00:00:08 |           4 | humidity    |    35 |
| 17 | 2010-01-01 00:00:16 |           4 | temperature |    19 |
| 18 | 2010-01-01 00:00:17 |           4 | dew_point   |    24 |
+----+---------------------+-------------+-------------+-------+

感谢您的回复！

根据字段组合选择最新结果

4 个答案: