干净的方法来检测current_query()是否是一个准备好的语句?

时间:2016-07-03 14:24:09

标签: postgresql

有没有人知道检测current_query()的结果是否是预备声明的好方法?

我似乎不能简单地使用字符串函数,因为这可能是准备语句的一个例子:

UPDATE table SET "x" = $1 WHERE "y" = $2 AND "z" = $3

但这不会:

UPDATE table SET "x" = '$1 + $2 = $3' WHERE "y"='$1' AND "z" = 1

是否有其他功能可以与/ {代替current_query()一起使用,或者您有其他想法吗?

1 个答案:

答案 0 :(得分:0)

您可以通过在剥离所有字符串的文本后查找\$[[:digit:]]来检测current_query()是否为预准备语句。以下查询可以执行,但在复杂引用嵌套的情况下可能会失败:

with 
  queries(curr_query) as (
       values ($$UPDATE table SET "x" = '$1||''a'' + $2 = $3' WHERE "y"='$1' AND "z" = 1$$),
              ($$UPDATE table SET "x" = $r1$a$r1$||$1 WHERE "y" = $2 AND "z" = $3||$r1$b$r1$ $$),
              ($$UPDATE table SET "x" = $1 WHERE "y" = $2 AND "z" = $3$$)
    ),
  stripped as (
    select *, 
       regexp_replace(
         regexp_replace(
           regexp_replace(curr_query, '(["'']).*?\1', '', 'g'),
           '\$([[:alpha:]]*?)\$.*?\$\1\$', '', 'g'),
         '\$([[:alpha:]][[:alnum:]]*?)\$.*?\$\1\$', '', 'g') as stripped_query
    from queries
    )
select *, stripped_query ~ '\$[[:digit:]]' AS is_prepared
from stripped