Question

第1次

显示

的输出

Msg Ardy Button Msg Ardy Button Msg Ardy Button Msg Ardy Button Msg Ardy Button Msg Ardy Button Msg John Button

<?php 

include('connection.php');
$sqlsearch = "SELECT * FROM chat WHERE recievernumber = $empnumnum and Notification = '0' ORDER BY chat_id ASC";
$resultsearch = mysqli_query($conn, $sqlsearch);
if ($resultsearch->num_rows > 0) {
// output data of each row

while($rowsearch = $resultsearch->fetch_assoc()) { 


echo " 
  <tr>

    <td>$rowsearch[msg]</td>
    <td style='list-style-type: none; color:white;' class='chatlist' data-employeeid='".$rowsearch['employeeid']."' data-fullname='".$rowsearch['user']."'> $rowsearch[user] </td>
    <td><button class='chatlist' data-employeeid='".$rowsearch['employeeid']."' data-fullname='".$rowsearch['user']."'>Read</button></td>    
  </tr>";                                                                     

}
}
?>

所以我尝试删除多个Ardy Msgs，因此我使用下面的代码。但结果是。发生的唯一正确的事情是员工ID。因为它有foreach（$ id2作为$ value）我在思考我是否可以使用2 foreach来解决它。但我不知道如何。

Msg John Button Msg John Button

第二

<?php

$sqlsearch = "SELECT DISTINCT  * FROM chat WHERE recievernumber = $empnumnum and Notification = '0'";
$resultsearch = mysqli_query($conn, $sqlsearch);
if ($resultsearch->num_rows > 0) {
while($rowsearch = $resultsearch->fetch_assoc()) { 
$id = $rowsearch['employeeid'];
$id1[] = $id;

$name = $rowsearch['user'];
  $name1[] = $name;
  $msg = $rowsearch['msg'];
  $msg1[] = $msg;


}
$id2 = array_unique($id1);
foreach ($id2 as $value){


echo " 
  <tr>

    <td>".$msg."</td>
    <td style='list-style-type: none; color:white;' class='chatlist' data-employeeid='".$value."' data-fullname='".$name."'> $name </td>
    <td><button class='chatlist' data-employeeid='".$value."' data-fullname='".$name."'>Read</button></td>    
  </tr>";                                                                     
}
}
?>

为什么重复我的第一个数组的结果而不是第二个用户

0 个答案: