Question

我已经实现了Jint - C＃中的javascript引擎。问题是它不支持已删除的unescape / escape函数，并且替代方法不会返回完全相同的结果。与此实现相同：http://cwestblog.com/2011/05/23/escape-unescape-deprecated/

Answer 1

由于没有人回复我必须自己从Ecma规范中编写两个已弃用的encode和decode函数。 Standard ECMA-262 5.1 Edition / June 2011。很抱歉，如果这些内容写得不够强大，我不是javascript开发人员。

var escape = function (s) {
s = s.toString(s);
var n = s.length;
var result = "";

for(var k = 0; k < n; k++) {
    var c = s[k];
    var S = "";
    var code = c.charCodeAt(0);

    if(("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789@*_+-./").indexOf(c) > -1) {
        S = c;
    }
    else if(code < 256) {
        S = '%' + code.toString(16);
    }
    else {
        S = code.toString(16);
        S = "%u" + ("0000").substring(0, 4 - S.length) + S; 
    }
    result = result + S;
}
return result;};

var unescape = function (s) {
s = s.toString(s);
var n = s.length;
var result = "";

for(var k = 0; k < n; k++) {
    var c = s[k];
    if(c == '%') {
        if(k <= (n - 6)) {
            if(s[k + 1] == 'u') {
                if(("0123456789abcdef").indexOf(s[k + 2]) > -1 &&
                   ("0123456789abcdef").indexOf(s[k + 3]) > -1 &&
                   ("0123456789abcdef").indexOf(s[k + 4]) > -1 &&
                   ("0123456789abcdef").indexOf(s[k + 5]) > -1) {
                        c = String.fromCharCode(parseInt(s.substring(k + 2, k + 7), 16));
                        k = k + 5;
                   }
                   else {
                        if(k <= (n - 3) && 
                        ("0123456789abcdef").indexOf(s[k + 1]) > -1 && 
                        ("0123456789abcdef").indexOf(s[k + 2]) > -1)
                        {
                            c = String.fromCharCode(parseInt(("00" + s.substring(k + 1, k + 3)), 16));
                            k = k + 2;
                        }
                   }
            }
            else {
                if(k <= (n - 3) && 
                  ("0123456789abcdef").indexOf(s[k + 1]) > -1 && 
                  ("0123456789abcdef").indexOf(s[k + 2]) > -1) {
                    c = String.fromCharCode(parseInt(("00" + s.substring(k + 1, k + 3)), 16));
                    k = k + 2;
                }
            }
        }
        else if(("0123456789abcdef").indexOf(s[k + 1]) > -1 &&
                ("0123456789abcdef").indexOf(s[k + 2]) > -1) {
            c = String.fromCharCode(parseInt(("00" + s.substring(k + 1, k + 3)), 16));
            k = k + 2;
        }
    }
    result = result + c;
}

return result;};

Javascript unescape函数定义？

1 个答案: