如何为从Alamofire收到的数据设置变量的值?

时间:2016-07-03 03:19:45

标签: ios json swift asynchronous alamofire

我有一个函数来获取JSON格式的电影列表,如下所示:

var size: Int = 0

func getMovies() {
    Alamofire.request(.GET, "https://api.themoviedb.org/3/discover/movie", parameters: ["sort_by" : "popularity", "api_key" : "secret api key"])
        .validate()
        .responseJSON { response in
            switch response.result {
            case .Success:
                self.json = JSON(response.result.value!)
                self.arraySize = self.json["results"].count
                for num in 0...self.arraySize - 1 {
                    let x = self.json["results"][num]["popularity"]
                    self.movieArray.append(x.double!)
                }
                self.movieArray.sortInPlace()
                for num in 0...self.arraySize - 1 {
                    let path = NSIndexPath(forRow: num, inSection: 0)
                    let cell = self.tableView.cellForRowAtIndexPath(path)
                    cell?.textLabel?.text = (self.findMovieByPopularity(self.movieArray[num]) + ":    " + String(self.movieArray[num]))
                }
                size = self.json["results"].count
            case .Failure(let error):
                print(error)
            }
    }
}

case .Success:的末尾,我尝试将我在函数外部声明的变量size设置为JSON中一个属性的长度。但是,当我在交换机外部使用此变量时,其值仍为0.

如何将size设置为属性的长度,并且能够在函数外部使用它?

1 个答案:

答案 0 :(得分:0)

添加一个完成处理程序并在闭包中分配值,如下所示:

func getMovies(completion: (aSize: Int) -> ()) {

let someSize: Int! 
//your code
case .Success:
               //your code
               let x = self.json["results"][num]["popularity"]
                    self.movieArray.append(x.double!)
                someSize = self.json["results"].count
                }
  completion(aSize: someSize)
//your code 

然后当你想在其他函数调用中调用它时:

getMovies {numSize in

self.size = numSize

}