Question

我在swift中创建了预订对象，

import Foundation

class BookingObject {
    var bookingTitle: String = ""
    var bookingDesc: String = ""
}

然后添加数据如下

private var bookingData:NSMutableArray?
for country in countryCode  {
    bookingObj.bookingTitle = country.name
    bookingObj.bookingDesc = country.name
    bookingData?.addObject(bookingObj)
}

并且在检索值

时出现问题

func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
    /* error found that line */
    let bookingObj:BookingObject! = bookingData?.objectAtIndex(indexPath.row)
    let cell = bookingTable.dequeueReusableCellWithIdentifier("BookCell", forIndexPath: indexPath) as! BookCell
    cell.lbAppointmentTitle.text = bookingObj.bookingTitle
    return cell   
}

请让我知道我错误地泄露了这个错误

无法转换类型＆＃39; AnyObject的值？＆＃39;到指定的类型＆＃39; BookingObject＆＃39;！

Answer 1

使用结构和CustomStringConvertible协议：

struct Booking : CustomStringConvertible {
    let title : String
    var description : String { return title }
}

声明bookings属性，如下所示：

private var bookings : [BookingObject] = []

添加以下内容：

for country in countryCode {
    bookings(Booking(title: country.name))
}

获取您的商品：

let booking = bookings[indexPath.row]

Answer 2

Kametrixom的回答将起作用，而且你应该完整地做。您的具体问题是数组的声明，该声明应为[BookingObject]。您需要进行其他更改，因为类对象具有引用语义，并且您只有其中一个。

无法转换类型＆＃39; AnyObject的值？＆＃39;指定类型＆＃39; BookingObject！＆＃39;

2 个答案: