Question

如何在以下查询中过滤row_number == 1：

query = session.query(Foo, func.row_number().over(
        partition_by=Foo.foo_field, order_by=desc(Foo.foo_date_time)).label("row_number"))

    query = query.filter(Foo.time_key <= time_key)
    # query = query.filter(row_number == 1)
    result = query.all()

Answer 1

我找到了它：

    row_number_column = func.row_number().over(partition_by=Foo.foo_field, order_by=desc(Foo.foo_date_time)).label('row_number')
    query = self.session.query(Foo)
    query = query.filter(Foo.time_key <= time_key)
    query = query.add_column(row_number_column)
    query = query.from_self().filter(row_number_column == 1)

Answer 2

也可以使用子查询来完成：

sshd_config

通过将row_number添加为列，它基本上会生成等效的SQL语句。

编译语句。

sub_query = session.query(
Foo,
func.row_number().over(partition_by=Foo.foo_field, order_by=desc(Foo.foo_date_time)).label("row_number")
)
sub_query = sub_query.filter(Foo.time_key <= time_key).subquery()
query = session.query(sub_query).filter(sub_query.c.row_number == 1)

将生成以下内容：

sub_query = session.query(
Foo,
func.row_number().over(partition_by=Foo.foo_field, order_by=desc(Foo.foo_date_time)).label("row_number")
)
sub_query = sub_query.filter(Foo.time_key <= time_key).subquery()
query = session.query(sub_query).filter(sub_query.c.row_number == 1)

str(query.statement.compile())

在sqlalchemy中按row_number过滤

2 个答案: