Question

我必须遵循以下代码：

 <select class="form-control" name="user">
    <?php
      $sql = "SELECT * FROM user ORDER BY lastname";
      $result = $conn->query($sql);
      if ($result->num_rows > 0) {
          // output data of each row
          while($row = $result->fetch_assoc()) {
            ?><option><?php echo $row["firstname"] . " " . $row["middlename"] . " " . $row["lastname"]; ?></option><?php
          }
      } else {
      }
    ?>
  </select>

表单的方法是get。我希望用户ID在get中设置，而不是现在发生的，firstname + Middlename + Lastname。所以我不想：webpage.php？user = firstname + middlename + lastname但我想要webpage.php？user = $ id

Answer 1

请在选项中取值属性，请尝试此代码。因为您没有传递用户ID。请在值中输入正确的字段，因为我不知道表中用户ID字段的名称，所以请更改

<select class="form-control" name="user">
    <?php
      $sql = "SELECT * FROM user ORDER BY lastname";
      $result = $conn->query($sql);
      if ($result->num_rows > 0) 
      {
          // output data of each row
          while($row = $result->fetch_assoc()) {
          ?>
          <option value="<?php echo echo $row["id"]; ?>"><?php echo         $row["firstname"] . " " . $row["middlename"] . " " . $row["lastname"]; ?>
          </option>
      <?php
      }
      }
      else {
      }
    ?>
  </select>

选项＆GT;

选择用户PHP

1 个答案: