Question

我尝试做类似的事情：

from BeautifulSoup import BeautifulSoup
import urllib2,unicodedata
import re

for x in range(1,105):

html_page = urllib2.urlopen('http://xxxxxx/BUSCAR/H=1;OR=5;ST=;LIST_ART_PAGENUMBER='+str(x)+';/Dxxxxx.aspx')
soup = BeautifulSoup(html_page)
for link in soup.findAll('a', attrs={'href': re.compile("^http://xxxxxx/PRODUCTO/PROD_ID")}):
    print link.get('href')

提取链接。我正确提取链接。但我想提取1到105的范围

但这不起作用！

error: expected an indented block

Answer 1

启动for循环时需要缩进。试试这个：

from BeautifulSoup import BeautifulSoup
import urllib2,unicodedata
import re

for x in range(1,105):

    html_page = urllib2.urlopen('http://xxxxxx/BUSCAR/H=1;OR=5;ST=;LIST_ART_PAGENUMBER='+str(x)+';/Dxxxxx.aspx')
    soup = BeautifulSoup(html_page)
    for link in soup.findAll('a', attrs={'href':re.compile("^http://xxxxxx/PRODUCTO/PROD_ID")}):
         print link.get('href')

对于，html和美丽的汤

1 个答案: