Question

我有一个看起来像这样的表：

Slug | Parent | MetaTitle | MetaDescription | MetaKeywords

只要父级不为空，就可以通过将slug附加到父级来构建网站上的Url。所以，如果我有这样的数据：

Slug            | Parent
-----------------------------------------
Home              null
About             null
Our-Company       About
Our-History       Our-Company

我希望能够运行一个能让我

的查询

/Home
/About
/About/Our-Company
/About/Our-Company/Our-History

这可能吗？任何帮助都会很棒!!!

Answer 1

可以使用recursive CTE：

declare @URLTable table (
 Slug varchar(50),
 Parent varchar(50)
)

insert into @URLTable
 (Slug, Parent)
 values
 ('Home', null),
 ('About', null),
 ('Our-Company', 'About'),
 ('Our-History', 'Our-Company')


;with cteURLs as (
 select Slug, cast('/' + Slug as varchar(1000)) as URL
     from @URLTable
     where Parent is null
 union all
 select u.Slug, cast(c.URL + '/' + u.Slug as varchar(1000)) as URL
     from @URLTable u
         inner join cteURLs c
             on u.Parent = c.Slug
)
select URL from cteURLs

输出结果为：

URL
-----------------
/Home
/About
/About/Our-Company
/About/Our-Company/Our-History

SQL Server：从单个表中获取所有父子URL

1 个答案: