Question

所以，我一直在编写这个程序，它接受一个HTMl文件，替换一些文本并将返回放回另一个目录中的不同文件。

发生此错误。

    Traceback (most recent call last):
      File "/Users/Glenn/jack/HTML_Task/src/HTML Rewriter.py", line 19, in <module>
        with open (os.path.join("/Users/Glenn/jack/HTML_Task/src", out_file)):
              File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/posixpath.py", line 89, in join
        genericpath._check_arg_types('join', a, *p)
      File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/genericpath.py", line 143, in _check_arg_types
        (funcname, s.__class__.__name__)) from None
    TypeError: join() argument must be str or bytes, not 'TextIOWrapper'

以下是我的代码。有没有人得到我可以实施的任何解决方案，或者我应该用火来杀死它。

    import re
    import os
    os.mkdir ("dest")

    file = open("2016-06-06_UK_BackToSchool.html").read()
    text_filtered = re.sub(r'http://', '/', file)
    print (text_filtered)

    with open ("2016-06-06_UK_BackToSchool.html", "wt") as out_file:
        print ("testtesttest")

    with open (os.path.join("/Users/Glenn/jack/HTML_Task/src", out_file)):
               out_file.write(text_filtered)

    os.rename("/Users/Glenn/jack/HTML_Task/src/2016-06-06_UK_BackToSchool.html", "/Users/Glenn/jack/HTML_Task/src/dest/2016-06-06_UK_BackToSchool.html")

Answer 1

with open (os.path.join("/Users/Glenn/jack/HTML_Task/src", out_file)):

out_file如果TextIOWrapper，则不是字符串。

os.path.join将字符串作为参数。

不要将关键字名称用作变量。 file是关键字。
请勿在函数调用os.mkdir ("dest")

Answer 2

尝试改变这个：

with open ("2016-06-06_UK_BackToSchool.html", "wt") as out_file

就此：

with open ("2016-06-06_UK_BackToSchool.html", "w") as out_file:

或者这个：

with open ("2016-06-06_UK_BackToSchool.html", "wb") as out_file:

TypeError - 这个错误是什么意思？

2 个答案: