Question

url="www.example.com/thedubaimall"

我想保存com/之后的所有内容，我只需要thedubaimall

我如何使用正则表达式？

Answer 1

强制性的“如果你没有使用正则表达式怎么办？”回答：

>>> url="www.example.com/thedubaimall"
>>> url.partition(".com/")[2]
'thedubaimall'

Answer 2

如果您想使用正则表达式，请使用re.findall：

re.findall('(?<=com/).*$', "www.example.com/thedubaimall")
# ['thedubaimall']

使用@ DeepSpace的建议进行一些速度测试：

%timeit re.findall('(?<=com/).*$', "www.example.com/thedubaimall")
# The slowest run took 7.57 times longer than the fastest. This could mean that an intermediate result is being cached.
# 1000000 loops, best of 3: 1.29 µs per loop

%timeit re.findall('com/(.*)', "www.example.com/thedubaimall")
# The slowest run took 6.48 times longer than the fastest. This could mean that an intermediate result is being cached.
# 1000000 loops, best of 3: 992 ns per loop

%timeit "www.example.com/thedubaimall".partition(".com/")[2]
# The slowest run took 7.87 times longer than the fastest. This could mean that an intermediate result is being cached.
# 1000000 loops, best of 3: 204 ns per loop

看起来@ DeepSpace的建议有点快，@ Kevin的答案要快得多。

使用正则表达式

2 个答案: