Question

我在Access数据库中有一个表，其中唯一的信息是：

start_time (date & time);
end_time (date & time);
duration (int, seconds);

我的输出中需要的是每小时花费的时间。

一个例子：

start_time: 2016/07/01 09:00:00
end_time: 2016/07/03 09:00:00

在此示例中，假装输出为：

Date      | Hour | Duration
2016/07/01   9     3600
2016/07/01   10    3600
2016/07/01   11    3600
2016/07/01   12    3600
   ...       ...    ...
2016/07/03   8     3600

提前致谢。

Answer 1

如果您只计算整个小时，则会执行以下操作：

PARAMETERS 
    StartDate DateTime, 
    EndDate DateTime;
SELECT 
    DateValue(DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])) AS [Date], 
    Hour(DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])) AS [Hour], 
    DateDiff("s",
        DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate]),
        DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10)+1,[StartDate])) AS Duration
FROM 
    MsysObjects AS Uno, 
    MsysObjects AS Deca
GROUP BY 
    DateValue(DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])), 
    Hour(DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])), 
    DateDiff("s",
        DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate]),
        DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10)+1,[StartDate])), DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])
HAVING 
    DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])<=[EndDate];

修改

您可以直接包括您的表格（持续时间）：

SELECT DateValue(DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])) AS [Date], Hour(DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])) AS [Hour], DateDiff("s", DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate]), DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10)+1,[StartDate])) AS Duration FROM MsysObjects AS Uno, MsysObjects AS Deca, Durations WHERE DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])<=[EndDate] GROUP BY DateValue(DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])), Hour(DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])), DateDiff("s", DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate]), DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10)+1,[StartDate]));

尊重分钟和秒数：

SELECT DateValue(DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])) AS [Date], Hour(DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])) AS [Hour], DateDiff("s", IIf(DateDiff("h",[StartDate],DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate]))=0, [StartDate], DateValue([StartDate])+TimeSerial(Hour([StartDate])+10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),0,0)), IIf(DateDiff("h",[EndDate],DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate]))=0, [EndDate], DateValue([StartDate])+TimeSerial(Hour([StartDate])+10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10)+1,0,0))) AS Duration FROM MsysObjects AS Uno, MsysObjects AS Deca, Durations WHERE DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])<[EndDate] GROUP BY DateValue(DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])), Hour(DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate])), DateDiff("s", IIf(DateDiff("h",[StartDate],DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate]))=0, [StartDate], DateValue([StartDate])+TimeSerial(Hour([StartDate])+10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),0,0)), IIf(DateDiff("h",[EndDate],DateAdd("h",10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10),[StartDate]))=0, [EndDate], DateValue([StartDate])+TimeSerial(Hour([StartDate])+10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10)+1,0,0)));

Answer 2

我设法添加了我想要的表格并且正在运行。但是，当我问第一个问题时，我可能不太清楚。

我想要的是按小时计算的持续时间。您给我的查询将始终返回3600作为持续时间（无论开始日期和结束日期是什么时间）。

这是我在表格中的1条记录的真实示例：

dealerimage

有了这条记录，我想知道的是：

campaign    agent   start_time              end_time
279          542    23/05/2016  17:05:21    24/05/2016 09:58:54

请注意，在第一行和最后一行中，我有start_time和下一小时之间的差异。

MS Access按小时计算秒数

2 个答案: