Question

我们想用新行字符（\ n）将字符串换成字符串。基本上，我们按ENTER键开始一个新行。

这是Enter键，用于在按下时在我们的消息中创建新行。

输入数据：

在注释列中捕获字符串。给出的评论栏是：

EDI ORDER-SAVE COMMENTS\nC3 Generic\nLOC 0833\nExpected arrival 01/07/2016\nOTYPE NE\nTRKPC 01 GM/00007643020008361321

我们尝试过：

string s = "EDIORDER-SAVE COMMENTS C3 Generic LOC 0833 Expected arrival 01/07/2016  OTYPE NE TRKPC 01 GM/00007643020008361321"  ;

StringBuilder sb = new StringBuilder(s);

int i = 0;
while ((i = sb.indexOf(" ", i + 20)) != -1) {
    sb.replace(i, i + 1, "\n");
}

转型后的预期数据： linebreak是新行字符

Long  String of Comment field  should Splits in 6 different lines 

EDI ORDER-SAVE COMMENTS

C3 Generic

LOC 0833

Expected arrival 01/07/2016

OTYPE NE

TRKPC 01 GM/00007643020008361321

输出后的确切数据如下所示：

SalesOrder    NComment                            SalesOrderLine                    StockCode
183590  EDI ORDER-SAVE COMMENTS                         1                                 
183590                                                  2                         abc-defg-13OZ-24              
183590  C3    Generic                                   37                                
183590  LOC 0833                                        38                                
183590  Expected arrival               01/07/2016       39                                
183590  OTYPE NE                                        40                                
183590  TRKPC 01 GM/00007643020008361321                51

非常感谢任何帮助！

Answer 1

对不起，我没有真正得到你想要达到的目标。你想在传递第20个字符的单词之前插入休息吗？

    StringBuilder sb = new StringBuilder(s);
    int currentSpaceFound = sb.indexOf(" ");
    int i = 1;
    while (currentSpaceFound != -1) {
        int lastOccurence = currentSpaceFound;
        currentSpaceFound = sb.indexOf(" ", currentSpaceFound + 1);
        if (currentSpaceFound > (20 * i)) {
            sb.setCharAt(lastOccurence, '\n');
            i++;
        }
    }
    System.out.println(sb);

Answer 2

我认为这样的事情应该有效：

private String wrapComment(String comment, int length) {

    if(comment.length() <= length) return comment;

    StringBuilder stringBuilder = new StringBuilder(comment);

    int spaceIndex = -1;

    for(int i = 0; i < comment.length(); i ++) {

        if(i % length == 0 && spaceIndex > -1) {
            stringBuilder.replace(spaceIndex, spaceIndex+1, "\n");
            spaceIndex = -1;
        }

        if(comment.charAt(i) == ' ') {
            spaceIndex = i;
        }

        stringBuilder.append(comment.charAt(i));
    }

    return stringBuilder.toString();
}

测试：

String comment = "EDI ORDER-SAVE COMMENTS C3 Generic LOC 0833 Expected arrival 01/07/2016  OTYPE NE TRKPC 01 GM/00007643020008361321";
System.out.println(wrapComment(comment, 30));

输出：

EDI ORDER-SAVE COMMENTS C3
Generic LOC 0833 Expected
arrival 01/07/2016  OTYPE NE TRKPC
01 GM/00007643020008361321

Java字符串环绕：如何在字符串中换行新行字符（\ n）

2 个答案: