Question

我有一个三表Userregistration，paytransaction和requesttransaction，其中我必须从所有表中获取具有相同用户ID和手机号码的数据，其中我已经获得了来自用户和touser的详细信息，如fromname，fromnumber，fromemail和详细信息touser是toname，tonumber但是我也无法获得用户的电子邮件ID，它会根据联系电话号码找到.Below是我的表结构。

放在userRegistration

id   contactname    mobile_no     email
.................................................
5     varun         8817          abc@gmail.com
112   chetan        1234          def@gmail.com

paytransaction

id userid  fromname  fromnumber tocontactname   tocontactnumber  status
...........................................................................
1    5       varun     8817       chetan           1234            pay

requesttransaction

id userid  fromname  fromnumber tocontactname   tocontactnumber  status
...........................................................................
1    112    chetan     1234       varun           8817        request
2    112    chetan     1234       ankit           123         request

如果用户在用户表中注册，则需要此输出，然后获取电子邮件ID，否则为comeblank

id userid  fromname  fromnumber  fromemail       tocontactname    tocontactnumber  toemail       status
    ...........................................................................
1    5     varun      8817       abc@gmail.com        chetan           1234      def@gmail.com   pay
3   112    chetan     1234      def@gmail.com          varun           8817      abc@gmail.com   request
4   112    chetan     1234      def@gmail.com           ankit           123                      request

这里ankit用户没有注册，所以他的toemail id为空白，我使用了以下查询，但我无法找到基于cotactnumber.e的toemailid尝试了以下查询，但我无法获得toemail id。< / p>

SELECT Userregistration.`id`,paytransaction.`id`,paytransaction.`userid`,paytransaction.`fromname`,paytransaction.`fromnumber`,Userregistration.email as fromemail,paytransaction.`contactname` as toname,paytransaction.`contactnumber` as tonumber FROM `paytransaction` INNER JOIN Userregistration ON paytransaction.`userid`=Userregistration.`id` UNION SELECT Userregistration.`id`,requesttransaction.`id`,requesttransaction.`userid`,requesttransaction.`fromname`,requesttransaction.`fromnumber`,Userregistration.email as fromemail,requesttransaction.`contactname` as toname,requesttransaction.`contactnumber` as tonumber FROM `requesttransaction` INNER JOIN Userregistration ON requesttransaction.`userid`=Userregistration.`id`

Answer 1

如果我理解你想要获得什么，你应该使用两个内连接而不是一个联合

SELECT 
    a.`id`
    ,requesttransaction.`id`
    ,requesttransaction.`userid`
    ,requesttransaction.`fromname`
    ,requesttransaction.`fromnumber`, 
    ,a.email as fromemail 
    ,requesttransaction.`toname`
    ,requesttransaction.`tonumber`,         
    ,b.email as toemail 
    ,requesttransaction.`contactname` as toname2
    ,requesttransaction.`contactnumber` as tonumber2
    FROM requesttransaction
    left JOIN Userregistration as a  ON requesttransaction.`fromnumber`= a.`mobile_no` 
    left JOIN Userregistration as b  ON requesttransaction.`tonumber`= b.`mobile_no`

如何在两列匹配的基础上从两个表中获取数据

1 个答案: