如何将MongoDB文档转换为JSON对象

时间:2016-07-01 11:25:14

标签: json node.js mongodb

我正在尝试使用查询返回的MongoDB文档发出一个帖子请求,因为服务器上的NodeJS.But中的请求主体我收到错误:无效的JSON。下面是我试图发布的文件

{
    "_id" : ObjectId("5739a6bf3f1b41477570dc89"),
    "taskCount" : 2,
    "study" : "cod",
    "phase" : "mansa2",
    "rhimeTaskId" : "5739a6bec4567f6e737fd3db",
    "recordId" : "5726f3cfc4567f6e737fc3ab",
    "recordStudy" : "codstudy",
    "recordPhase" : "mansa2",
    "recordLanguage" : "Punjabi",
    "recordScript" : "Latin",
    "_state" : "CodingComplete",
    "tasks" : [
        {
            "physician" : ObjectId("5739a6bd3f1b41477570dc78"),
            "stage" : "Coding",
            "result" : {
                "cod" : "C15",
                "feedback" : {
                    "narrativeLength" : "Adequate",
                    "positiveSymptomsIncluded" : "Only Positive",
                    "certainty" : "High"
                },
                "keywords" : [
                    "52 yr male, died of food pipe cancer, suffered pain upper abdomen, investigated,FNAC confirmed Cancer, Put on Chemotherapy, multiple cycles, died at home, had fever with chills occasionally"
                ]
            }
        },
        {
            "physician" : ObjectId("5739a6bd3f1b41477570dc79"),
            "stage" : "Coding",
            "result" : {
                "cod" : "C15",
                "feedback" : {
                    "narrativeLength" : "Inadequate",
                    "positiveSymptomsIncluded" : "Only Positive",
                    "certainty" : "High"
                },
                "keywords" : [
                    "severe pain abdomen, ultrasonography revealed food pipe cancer, chemotherapy given, died"
                ]
            }
        }
    ],
    "__v" : 2
}

这是我编写的用于发出POST请求的代码

var MongoClient = require('mongodb').MongoClient;
var request = require('request');
var assert = require('assert');
var cmeprovisioning= 'mongodb://localhost:27017/cmeprovisioning';

MongoClient.connect(cmeprovisioning, function(err, db) {
  assert.equal(null, err);
  var count=0;
  console.log("Connected to cmeprovisioning");

         var cursor =db.collection('rhimeReport').find(
                    {"study":"cod","phase":"mansa2","recordStudy":"codstudy",
                     "recordPhase":"mansa2","_state":"CodingComplete"
                    });


                 cursor.each(function(err, doc) {
                      assert.equal(err, null);
                      if (doc != null) {
                         console.dir(doc);
                         count=count+1;
                         request({url: "http://cme.host.net:8081/cme-provisioning/update",
                                  method: "POST",json: true,
                                  headers: {"content-type": "application/json"},
                                  json: doc
                                 },function(e,r,b){

                                       console.log("POST Error "+count+" "+e)
                                       console.log("POST Response "+count+" "+r)
                                       console.log("POST BODY "+count+" "+b)
                                 });


                      } else {
                         console.log("Some Error : "+err)
                      }
                   });
});

我也尝试过使用JSON.stringify(doc),但仍然遇到了无效的JSON错误。有没有办法可以使用find查询返回的mongo文档并将其转换为JSON来发出POST请求。

我认为那些ObjectID是使它成为无效的JSON文档的原因。

4 个答案:

答案 0 :(得分:2)

你需要将对象id转换为字符串ie。



var result = {
  "_id": ObjectId("5739a6bf3f1b41477570dc89"),
  "taskCount": 2,
  "study": "cod"
};
//now convert to string 
result=result._id.toString();
//now you can use the result




答案 1 :(得分:1)

试试这个,

var cursor =db.collection('rhimeReport').find(
       {"study":"cod","phase":"mansa2","recordStudy":"codstudy",
        "recordPhase":"mansa2","_state":"CodingComplete"});

cursor.toString();
......

希望得到这个帮助。

答案 2 :(得分:1)

这是实际答案:

如果要将mongo对象转换为JSON对象。 每个mongo对象toJSON

中都有一个实用程序方法

因此,您只需在响应对象上执行mongoResponseObject.toJSON()

例如

Products.findById(id).then(res => {
    const jsonRes = res.toJSON();
    // Here jsonRes is JSON
})

或者,您可以像这样使用.lean()直接获取JSON对象。

Products.findById(id).lean().then(res => {
    // Here res is JSON
})

答案 3 :(得分:0)

在robomongo中尝试

500px