我正在尝试在uialertcontroller文件中创建Config.swift，如下所示。
static func showAlertMessage(titleStr:String, messageStr:String) -> Void {
let window : UIWindow?
let alert = UIAlertController(title: titleStr, message: messageStr, preferredStyle: UIAlertControllerStyle.Alert);
self.window!.presentViewController(alert, animated: true, completion: nil)
}
问题是我在self.window!.
类型'Config'没有成员'window'
请让我知道如何解决这个问题。
答案 0 :(得分：27)
<强>迅速
这里是我使用的，这与@penatheboss回答相同，只是添加添加动作和处理程序的能力。
extension UIViewController {
func popupAlert(title: String?, message: String?, actionTitles:[String?], actions:[((UIAlertAction) -> Void)?]) {
let alert = UIAlertController(title: title, message: message, preferredStyle: .alert)
for (index, title) in actionTitles.enumerated() {
let action = UIAlertAction(title: title, style: .default, handler: actions[index])
alert.addAction(action)
}
self.present(alert, animated: true, completion: nil)
}
}
确保actionTitles和actions数组的计数相同。如果您不需要任何操作处理程序关闭，请传递 nil 。
self.popupAlert(title: "Title", message: " Oops, xxxx ", actionTitles: ["Option1","Option2","Option3"], actions:[{action1 in
},{action2 in
}, nil])
目标C ：
添加UIViewController
<强>的UIViewController + PopAlert.h
#import <UIKit/UIKit.h>
@interface UIViewController (UIViewControllerCategory)
- (void) popAlertWithTitle: (NSString*) title message: (NSString*) message actionTitles:(NSArray *) actionTitles actions:(NSArray*)actions;
@end
<强>的UIViewController + PopAlert.m
#import "UIViewController+PopAlert.h"
@implementation UIViewController (UIViewControllerCategory)
- (void) popAlertWithTitle: (NSString*) title message: (NSString*) message actionTitles:(NSArray *) actionTitles actions:(NSArray*)actions {
UIAlertController *alert = [UIAlertController alertControllerWithTitle:title message:message preferredStyle:UIAlertControllerStyleAlert];
[actionTitles enumerateObjectsUsingBlock:^(id _Nonnull obj, NSUInteger idx, BOOL * _Nonnull stop) {
UIAlertAction *action = [UIAlertAction actionWithTitle:obj style:UIAlertActionStyleDefault handler:actions[idx]];
[alert addAction:action];
}];
[self presentViewController:alert animated:YES completion:nil];
}
@end
<强>用法：
#import UIViewController+PopAlert.h
...
[super viewDidDisappear:animated];
NSArray *actions = @[^(){NSLog(@"I am action1");}, ^(){NSLog(@"I am action2");}];
[self popAlertWithTitle:@"I am title" message:@"good" actionTitles:@[@"good1", @"good2"] actions:actions];
答案 1 :(得分：17)
self.window意味着此类中有一个window对象，情况并非如此。
您需要将let window : UIWindow?与window?.presentViewController(alert, animated: true, completion: nil)一起使用，但这无济于事，因为此窗口实际上并不代表任何现有窗口，而且无论如何它都不是视图控制器。
所以我建议你将你将使用的实际视图控制器传递给方法：
static func showAlertMessage(vc: UIViewController, titleStr:String, messageStr:String) -> Void {
let alert = UIAlertController(title: titleStr, message: messageStr, preferredStyle: UIAlertControllerStyle.Alert);
vc.presentViewController(alert, animated: true, completion: nil)
}
然后从UIViewController对象可用的类中调用它。
答案 2 :(得分：4)
extension UIViewController{
// Global Alert
// Define Your number of buttons, styles and completion
public func openAlert(title: String,
message: String,
alertStyle:UIAlertController.Style,
actionTitles:[String],
actionStyles:[UIAlertAction.Style],
actions: [((UIAlertAction) -> Void)]){
let alertController = UIAlertController(title: title, message: message, preferredStyle: alertStyle)
for(index, indexTitle) in actionTitles.enumerated(){
let action = UIAlertAction(title: indexTitle, style: actionStyles[index], handler: actions[index])
alertController.addAction(action)
}
self.present(alertController, animated: true)
}
}
self.openAlert(title: "alert",
message: "add your message",
alertStyle: .alert,
actionTitles: ["Okay", "Cancel"],
actionStyles: [.default, .cancel],
actions: [
{_ in
print("okay click")
},
{_ in
print("cancel click")
}
])
self.openAlert(title: "actionsheet",
message: "add your message",
alertStyle: .actionSheet,
actionTitles: ["Okay", "Cancel"],
actionStyles: [.default, .cancel],
actions: [
{_ in
print("okay click")
},
{_ in
print("cancel click")
}
])
答案 3 :(得分：2)
我建议创建扩展程序：
extension UIViewController {
func showAlertMessage(titleStr:String, messageStr:String) {
let alert = UIAlertController(title: titleStr, message: messageStr, preferredStyle: UIAlertControllerStyle.Alert)
self.presentViewController(alert, animated: true, completion: nil)
}
}
答案 4 :(得分：2)
您可以尝试此操作，请在AppDelegate.swift文件中添加以下代码。
static func showAlertView(vc : UIViewController, titleString : String , messageString: String) ->()
{
let alertView = UIAlertController(title: titleString, message: messageString, preferredStyle: .alert)
let alertAction = UIAlertAction(title: "ok", style: .cancel) { (alert) in
vc.dismiss(animated: true, completion: nil)
}
alertView.addAction(alertAction)
vc.present(alertView, animated: true, completion: nil)
}
并从任何viewcontroller调用 showAlertView 方法
AppDelegate.showAlertView(vc: self, titleString: "testTitle", messageString: "test msg")
答案 5 :(得分：1)
我创建了一个alerMessage类。我可以调用我的应用程序中的任何位置
//Common Alert Message Class
class AlertMessage {
internal static var alertMessageController:UIAlertController!
internal static func disPlayAlertMessage(titleMessage:String, alertMsg:String){
AlertMessage.alertMessageController = UIAlertController(title: titleMessage, message:
alertMsg, preferredStyle: UIAlertControllerStyle.Alert)
AlertMessage.alertMessageController.addAction(UIAlertAction(title: "Ok", style: UIAlertActionStyle.Default,handler: nil))
if let controller = UIApplication.sharedApplication().keyWindow?.rootViewController?.presentedViewController {
controller.presentViewController(AlertMessage.alertMessageController, animated: true, completion: nil)
}
else{
UIApplication.sharedApplication().delegate?.window!!.rootViewController?.presentViewController(AlertMessage.alertMessageController, animated: true, completion: nil)
}
return
}
}
答案 6 :(得分：1)
请参考下面的GIT示例
https://github.com/amilaim/CommonAlertView
// ViewController.swift
// CommonAlertView
//
// Created by Amila Munasinghe on 4/25/17.
// Copyright © 2017 Developer Insight. All rights reserved.
//
import UIKit
class ViewController: UIViewController,AlertViewControllerDelegate {
@IBOutlet weak var AlertViewResultTextOutlet: UITextField!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
}
@IBAction func ShowAlertAction(_ sender: Any) {
let alert = AlertViewController.sharedInstance
alert.delegate = self
alert.SubmitAlertView(viewController: self,title: "Developer Insight", message: "Please enter any text value")
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
func SubmitAlertViewResult(textValue : String) {
AlertViewResultTextOutlet.text = textValue
}
}
常见的UIAlertViewController实现
import UIKit
protocol AlertViewControllerDelegate {
func SubmitAlertViewResult(textValue : String)
}
class AlertViewController {
static let sharedInstance = AlertViewController()
private init(){}
var delegate : AlertViewControllerDelegate?
func SubmitAlertView(viewController : UIViewController,title : String, message : String){
let alert = UIAlertController(title: title,
message: message,
preferredStyle: .alert)
// Submit button
let submitAction = UIAlertAction(title: "Submit", style: .default, handler: { (action) -> Void in
// Get 1st TextField's text
let textField = alert.textFields![0]
if(textField.text != "")
{
self.delegate?.SubmitAlertViewResult(textValue: textField.text!)
}
})
// Cancel button
let cancel = UIAlertAction(title: "Cancel", style: .destructive, handler: { (action) -> Void in })
// Add 1 textField and cutomize it
alert.addTextField { (textField: UITextField) in
textField.keyboardAppearance = .dark
textField.keyboardType = .default
textField.autocorrectionType = .default
textField.placeholder = "enter any text value"
textField.clearButtonMode = .whileEditing
}
// Add action buttons and present the Alert
alert.addAction(submitAction)
alert.addAction(cancel)
viewController.present(alert, animated: true, completion: nil)
}
}
答案 7 :(得分：1)
您可以使用我在Swift4中为Show Alert创建的Utility类。它只需编写单行代码即可轻松使用：
显示简单提醒
@IBAction func showDefaultAlert(_ sender: Any) {
Alert.showAlert(title:"Alert", message:"Default Alert")
}
答案 8 :(得分：0)
我建议你写这段代码，但如果你真的需要，试试这个：
static func showAlertMessage(titleStr:String, messageStr:String) -> Void {
let alert = UIAlertController(title: titleStr, message: messageStr, preferredStyle: UIAlertControllerStyle.Alert);
if let viewController = UIApplication.sharedApplication().windows.first?.rootViewController as UIViewController? {
viewController.presentViewController(alert, animated: true, completion: nil)
}
}
至少它不会崩溃。
@Eric D更好的答案。
答案 9 :(得分：0)
如果您想从AppDelegate窗口呈现，您可以像这样使用
UIApplication.sharedApplication().delegate?.window.rootViewController?.presentViewController(vc, animated: true, completion: nil)
答案 10 :(得分：0)
我根据@William Hu的解决方案使用的是什么：
func popup(caller:UIViewController, style:UIAlertControllerStyle? = UIAlertControllerStyle.alert,
title:String, message:String, buttonTexts:[String], buttonStyles:([UIAlertActionStyle?])? = nil,
handlers:[((UIAlertAction) -> Void)?], animated:Bool? = nil, completion: (() -> Void)? = nil) {
let alert = UIAlertController(title: title, message: message, preferredStyle: style!)
for i in 0..<buttonTexts.count {
alert.addAction(UIAlertAction(title: buttonTexts[i],
style: (buttonStyles == nil || i >= buttonStyles!.count || buttonStyles![i] == nil ?
UIAlertActionStyle.default : buttonStyles![i]!),
handler: (i >= handlers.count || handlers[i] == nil ? nil : handlers[i]!)))
}
caller.present(alert, animated: animated != nil ? animated! : true, completion: completion)
}
Alert，并且可以选择用于ActionSheet。buttonTexts，buttonStyles和handlers的大小可能不相等。Actions可以设置样式。Animated。 block。用法：
popup(caller: self, style: UIAlertControllerStyle.alert,
title: "Title", message: "Message",
buttonTexts: ["Destructive", "Cancel", "OK"],
buttonStyles: [UIAlertActionStyle.destructive, UIAlertActionStyle.cancel],
handlers: [nil], animated: false)
答案 11 :(得分：0)
这也是您可以在可用的View Controller之上显示的方式。
UIApplication.topViewController()?.present(alertViewController!, animated: true, completion: nil)