Question

我想找到迭代字符串并从中获取每个字符的方法。结果应该类似于数组的each_cons方法。

您现在关于一些现有方法或如何实现自己的方法吗？

Answer 1

使用String#each_char：

"abcdef".each_char.each_cons(3) { |a| p a }
["a", "b", "c"]
["b", "c", "d"]
["c", "d", "e"]
["d", "e", "f"]
=> nil

Answer 2

如果你想要＆＃34;连续字符串＆＃34;长度3：

r = /
    (?=       # begin a positive lookahead
      ((.{3}) # match any three characters in capture group 1
    )         # close the positive lookahead
    /x        # free-spacing regex definition mode

"abcdef".scan(r).flatten
  #=> ["abc", "bcd", "cde", "def"]

以传统方式编写，这个正则表达式是：

r = /(?=(.{3}))/

如果你想要一个包含三个字母的数组，请执行以下操作：

"abcdef".scan(/(?=(.{3}))/).flatten.map { |s| s.split('') }
  #=> [["a", "b", "c"], ["b", "c", "d"], ["c", "d", "e"], ["d", "e", "f"]]

Answer 3

补充其他答案。

"abcdef".each_char.to_a.in_groups_of(3)

从字符串中获取n个字符

3 个答案: