Question

我有这个＆＃34;课程＆＃34;：

function FindArrayObject(arr, property, value) {

    var $this = this;
    [ some code here ]
    return $this;

}

FindArrayObject.prototype.index = function() {
    return this.result;
};
FindArrayObject.prototype.element = function() {
    return ( this.result === -1 ? false : 'Something else' );
};

但是我想将它附加到Array原型，所以我不需要用new FindArrayObject初始化它并传递数组。

一个大问题是this会引用数组而不是类，所以我不知道我们是否可以，也会导致＆＃34; sub＆＃34;没有this的函数无法检索值，但我会尝试询问。

谢谢！

Answer 1

您可以使用public void CreateEnterpriseProjectType(Guid eptGuid, string eptName, string eptDescription) { ProjectContext pwaContext = new ProjectContext(this.PWA_URL); EnterpriseProjectTypeCreationInformation eptData = new EnterpriseProjectTypeCreationInformation(); eptData.Id = eptGuid; eptData.Name = eptName; eptData.Description = eptDescription; eptData.IsDefault = false; eptData.IsManaged = true; eptData.WorkspaceTemplateName = "PROJECTSITE#0"; eptData.ProjectPlanTemplateId = Guid.Empty; eptData.WorkflowAssociationId = Guid.Empty; eptData.Order = 4; List<ProjectDetailPageCreationInformation> projectDetailPages = new List<ProjectDetailPageCreationInformation>() { new ProjectDetailPageCreationInformation() { Id = pwaContext.ProjectDetailPages[1].Id, IsCreate = true } }; eptData.ProjectDetailPages = projectDetailPages; pwaContext.Load(pwaContext.EnterpriseProjectTypes); pwaContext.ExecuteQuery(); EnterpriseProjectType newEpt = pwaContext.EnterpriseProjectTypes.Add(eptData); pwaContext.EnterpriseProjectTypes.Update(); pwaContext.ExecuteQuery(); }。这将使该函数可用于您在脚本范围内初始化的所有数组。

Answer 2

Array.prototype.FindArrayObject = function (arr,property, value) {

    var $this = this;
    [ some code here ]

}

您可以像这样使用

var a = new Array.prototype.FindArrayObject([],'','')

附上＆＃34; class＆＃34;到Array原型

2 个答案: